The Hooke's law is a principal of physics that states that the force needed to extend or compress a spring by some distance x scales linearly with respect to that distance.
<h3><u>Given </u><u>:</u><u>-</u><u> </u></h3>
- A certain circuit is composed of two series resistors
- The total resistance is 10 ohms
- One of the resistor is 4 ohms
<h3>
<u>To </u><u>Find </u><u>:</u><u>-</u></h3>
- We have to find the value of other resistor?
<h3><u>Let's </u><u>Begin </u><u>:</u><u>-</u></h3>
We know that,
In series combination,
- When a number of resistances are connected in series, the equivalent I.e resultant resistance is equal to the sum of the individual resistances and is greater than any individual resistance
<u>That </u><u>is</u><u>, </u>
Rn in series = R1 + R2 + R3.....So on
<u>Therefore</u><u>, </u>
<u>According </u><u>to </u><u>the </u><u>question</u><u>, </u>
We have,
R1 + R2 = 10 Ω
4 + R2 = 10Ω
R2 = 10 - 4
R2 = 6Ω
Hence, The value of R2 resistor in series is 6Ω
Answer:
Star A is closer than Star B
Explanation:
As we know that in parallax method of distance measurement the angle subtended by the star when it covers a distance of one Parsec arc length, it is known as parallax angle
Here we can say

so we have

so here we have
angle subtended by Star A = 1 arc sec
angle subtended by star B = 0.75 arc sec
now we have
distance for star A is given as

distance of star B is given as

So star A is closer than star B