Which part of the microscope is the circular area on the stage that light passes through?

What is simple machines and it type.I need it today please

raketka [301]

Simple machines are tools, devices or objects that are used to make work easier.

TYPES OF SIMPLE MACHINES.

Levers
Inclined Plane
Wedges
Screw
Pulley
Wheel & Axle

THE LEVERS

A lever is simply a plank or ridge beam that is free to rotate on a pivot.

PARTS OF A LEVER

Load
Effort
Fulcrum or pivot

CLASSES OF LEVERS

THE FIRST CLASS LEVER

In this class, the FULCRUM is between the EFFORT and the LOAD. The mechanical advantage is more if the load is closer to the FULCRUM. Examples: seesaws, boat oars and crowbars.

THE SECOND CLASS LEVER

In this class, the LOAD is between the EFFORT and the FULCRUM. The mechanical advantage is more if the LOAD is closer to the FULCRUM. Example: wheelbarrow.

THE THIRD CLASS LEVER

In this class, the EFFORT is between the LOAD and the FULCRUM. The mechanical advantage is more if the EFFORT is closer to the LOAD. Example: garden shovel.

THE INCLINED PLANE OR RAMP

An inclined plane is a simple machine with a sloping surface. It makes it easier for us to move objects from lower grounds to higher grounds.

WEDGES

A wedge is simply a triangular tool, often made of wood, stone, metal or plastic. It is thick at one end and tapers to a thin or sharp edge at the other end. Examples: knife, axe, doorstopper, nail, blade on the snow plough or farmer grader.

PULLEY

A pulley is simply a wheel with a groove in it, and a rope in the groove. It is used to lift heavy objects from the ground to high places.

WHEEL & AXLE

Involves two circular objects joined at the center. It works when force is applied to the wheel or when force is applied to the axle. Example: door knob.

4 0

2 years ago

A 1 kg object can be accelerated at 10 m/s^2. If you apply this same force to a 4kg object, what will its acceleration be?

AleksAgata [21]

Answer:

$a2 = 2.5~m/s^2$

Explanation:

Mechanical Force

According to the second Newton's law, the net force F exerted by an external agent on an object of mass m is:

F = m.a

Where a is the acceleration of the object.

Assume we apply some given force F to an object of m1=1 Kg that produces an acceleration $a1=10 m/s^2$ , then:

F = m1.a1

The same force F is now applied to a second object m2=4 Kg that produces an acceleration a2, then:

F = m2.a2

Dividing both equations:

$\displaystyle 1=\frac{m1.a1}{m2.a2}$

Solving for a2:

$\displaystyle a2=\frac{m1.a1}{m2}$

Substituting values:

$\displaystyle a2=\frac{1*10}{4}$

$a2 = 2.5~m/s^2$

7 0

2 years ago

Suppose you increase your walking speed from 5 m/s to 14 m/s in a period of 3 s. What is your acceleration

kirza4 [7]

5-14 m/s in 3 seconds
a=vf-vi/t
a=14-5/3
a=9/3
a=3 m/s^2

4 0

2 years ago

A 0.89 m aqueous solution of an ionic compound with the formula mx has a freezing point of -3.0 ∘c . van't hoff factor?

BigorU [14]

Answer is: Van't Hoff factor (i) for this solution is 1,81.
Change in freezing point from pure solvent to solution: ΔT =i · Kf · b.
Kf - molal freezing-point depression constant for water is 1,86°C/m.
b - molality, moles of solute per kilogram of solvent.
b = 0,89 m.
ΔT = 3°C = 3 K.
i = 3°C ÷ (1,86 °C/m · 0,89 m).

i = 1,81.

5 0

3 years ago

You are pushing on a heavy desk with a force of 65 N the desk does not slide the force of friction between the desk and the floo

astra-53 [7]

When an object does not move even on pushing , static frictional force acts on in opposite direction of the applied force to stop the object from moving. static frictional force is a self adjusting force and it adjust its value according to the applied force if the applied force is smaller than the maximum value of static frictional force. The object starts moving once the applied force on it becomes greater than the maximum static frictional force. hence the statement is true.

7 0

3 years ago