Question

The product of a number and 3 more than twice that number is at most 152.

Answer 1

The quadratic equation that represents the product is $2n^{2}+3n-152\leq 0$.

We are given in the question that the product of a number and 3 more than twice that number is at most 152.

It is also given that the smaller number is represented by the expression n.

Hence, according to the question, the larger number will be:-

2n+3

The product of the two numbers will be :-

n(2n+3)

It is given that the product of the two numbers is at most 152.

Hence,

n(2n + 3) ≤ 152

Hence, the quadratic inequality comes out to be:-

$2n^{2}+3n\leq 152$

Taking 152 to the left hand side , we get the quadratic inequality,

$2n^{2}+3n-152\leq0$

To learn more about quadratic equation, here:-

brainly.com/question/17177510

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