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prohojiy [21]
3 years ago
8

What is the area of a cylindrical ring where the diameter of the cross section is 6.3 in and the center line has a length of 48

in
Mathematics
1 answer:
Nesterboy [21]3 years ago
4 0

Answer:

The area of cylinder 949.536 in²

Step-by-step explanation:

Points to remember

Curved surface area of cylinder = 2πrh

Where r - radius of cylinder

h - Height of cylinder

<u>To find the area of cylinder</u>

Here r = diameter/2 = 6.3/2 = 3.15 in

h = 48 in

Area =  2πrh

 = 2 * 3.14 * 3.15 * 48

= 949.536 in²

Therefore area of cylinder 949.536 in²

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Answer:

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Step-by-step explanation:

Let h represent the number of hamburgers. Then h+63 is the number of cheeseburgers, and the combined total is ...

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<em>Additional comment</em>

In a "sum and difference" problem like this, the smaller number is half the difference between the sum and the difference. h = (813 -63)/2 = 375. This generic solution applies to all "sum and difference" problems.

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