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julia-pushkina [17]
2 years ago
15

Two wires A and B with circular cross sections are made of the same metal and have equal lengths, but the resistance of wire A i

s three times greater than that of wire B. (ii) What is the ratio of the radius of A to that of B ? Choose from the same possibilities as in part (i).
Physics
1 answer:
AlexFokin [52]2 years ago
8 0

The resistance of wire B will be D. 1/2R

<h3>What is resistance?</h3>

It should be noted that resistance simply means the measure of the opposition to the current flow that's in an electric circuit.

Based on the information given, the resistance will be calculated thus:

= 2L/4A

= 1/2pL/A

= R/2

Therefore, the resistance of wire B will be D. 1/2R

Learn more about resistance in:

brainly.com/question/24858512

#SPJ4

Two wires A and B with circular cross sections are made of the same metal and have equal lengths, but the resistance of wire A is three times greater than that of wire B. (ii) What is the ratio of the radius of A to that of B

(a) 4 R (b) 2 R (c) R (d) 1/2R (e) 1/4R

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Given data:

* The mass of the book is 2 kg.

* The initial height of the book is 0.78 m.

* The final height of the book is 2.1 m.

Solution:

(A). The work done by the gravity on the book is,

W=mg(h_f-h_i)

where m is the mass, g is the acceleration due to gravity, h_i is the initial height and h_f is the final height,

The work is done in moving the object in upward direction where as the gravitational force is acting in the down ward direction. Thus, the value g (acceleration due to gravity) is taken as negative in this case.

Substituting the known values,

\begin{gathered} W=2\times(-9.8)\times(2.1-0.78) \\ W=-19.6\times1.32 \\ W=-25.9\text{ J} \end{gathered}

Thus, the work done by the gravitational force is -25.9 J.

(B). The work done by the hand on the moving the book is,

\begin{gathered} W_1=-W \\ =25.9\text{ J} \end{gathered}

Thus, the work done by the hand on the book is 25.9 J.

7 0
1 year ago
Which of the following statements best explains why elements in the same family of the periodic table have similar bonding prope
slava [35]

Answer: D. The elements have the same number of valence electrons

Explanation: The chemical reactivity of elements is governed by the valence electrons present in the element.

The elements present in the same group or vertical column have similar valence configurations and thus behave similarly in chemical reactions or have similar bonding properties.

For Example: Both fluorine and chlorine belong to same family or group and both have 7 electrons in their valence shell and thus accept single electron to attain noble gas configuration.

F:9:1s^22s^22p^5

F^-:10: 1s^22s^22p^6

Cl:17:1s^22s^22p^63s^23p^5

Cl^-:18:1s^22s^22p^63s^23p^6

thus both would bond with a cation bearing a single positive charge.

3 0
3 years ago
What are applications of zeroth law of thermodynamics?​
Harrizon [31]

Answer:

Applications of zeroth law of thermodynamics:

1. When we get very hot food, we wait to make it normal. In this case, hot food exchanges heat with surrounding and brings equilibrium.

2. We keep things in the fridge and those things come equilibrium with fridge temperature.

3. Temperature measurement with a thermometer or another device.

4. In the HVAC system, sensors or thermostats are used to indicate temperature. It always comes in a thermal equilibrium with room temperature.

5. If you and the swimming pool you’re in are at the same temperature, no heat is flowing from you to it or from it to you (although the possibility is there). You’re in thermal equilibrium.

6 0
3 years ago
What is the magnitude of the force needed to keep a 60 newton rubber block moving across level,dry asphalt in a straight line at
pantera1 [17]

let Coefficients of Friction of Rubber on asphalt (dry) =0.7

F= Coefficients of Friction * normal force = 0.7 * 60 =42 N

so the net force of the rubber is zero, meaning it will travel at a constant speed.

When the rubber is travel at 2m/s, 42N is required to keep moving at constant speed

6 0
4 years ago
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Ask Your Teacher Cam Newton of the Carolina Panthers throws a perfect football spiral at 6.9 rev/s. The radius of a pro football
faltersainse [42]

Answer:

a=159.32\ m/s^2

Explanation:

It is given that,

Angular speed of the football spiral, \omega=6.9\ rev/s=43.35\ rad/s

Radius of a pro football, r = 8.5 cm = 0.085 m

The velocity is given by :

v=r\omega

v=0.085\times 43.35

v = 3.68 m/s

The centripetal acceleration is given by :

a=\dfrac{v^2}{r}

a=\dfrac{(3.68)^2}{0.085}

a=159.32\ m/s^2

So, the centripetal acceleration of the laces on the football is 159.32\ m/s^2. Hence, this is the required solution.

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