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julia-pushkina [17]
1 year ago
15

Two wires A and B with circular cross sections are made of the same metal and have equal lengths, but the resistance of wire A i

s three times greater than that of wire B. (ii) What is the ratio of the radius of A to that of B ? Choose from the same possibilities as in part (i).
Physics
1 answer:
AlexFokin [52]1 year ago
8 0

The resistance of wire B will be D. 1/2R

<h3>What is resistance?</h3>

It should be noted that resistance simply means the measure of the opposition to the current flow that's in an electric circuit.

Based on the information given, the resistance will be calculated thus:

= 2L/4A

= 1/2pL/A

= R/2

Therefore, the resistance of wire B will be D. 1/2R

Learn more about resistance in:

brainly.com/question/24858512

#SPJ4

Two wires A and B with circular cross sections are made of the same metal and have equal lengths, but the resistance of wire A is three times greater than that of wire B. (ii) What is the ratio of the radius of A to that of B

(a) 4 R (b) 2 R (c) R (d) 1/2R (e) 1/4R

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3 years ago
A medical cyclotron used in the production of medical isotopes accelerates protons to 6.5 MeV. The magnetic field in the cyclotr
mart [117]

Answer:

diameter of largest orbit is 0.60 m

Explanation:

given data

isotopes accelerates KE = 6.5 MeV

magnetic field B = 1.2 T

to find out

diameter

solution

first we find velocity from kinetic energy equation

KE = 1/2 × m×v²   ........1

6.5 × 1.6 × 10^{-19} = 1/2 × 1.672 × 10^{-27} ×v²

v = 3.5 × 10^{7} m/s

so

radius will be

radius = \frac{m*v}{B*q}   ........2

radius =  \frac{1.672*10^{-27}*3.5*10^{7}}{1.2*1.6*10^{-19}}  

radius = 0.30

so diameter = 2 × 0.30

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8 0
3 years ago
Read 2 more answers
A motorcycle that is slowing down uniformly. The motorcycle covers 1 ????m=1000 m in 80 sec⁡. The motorcycle then covers the nex
Lynna [10]

Answer:

Part a)

acceleration = -0.042 m/s/s

Part b)

initial speed = 14.17 m/s

final speed = 5.77 m/s

Explanation:

Part a)

Let the initial velocity of the motorcycle is

v_i = v_o

now at the end of 80 s let the speed is

v_f = v_1

after another 120 s let the speed will be

v_f' = v_2

now we know that

d = \frac{v_i + v_f}{2} (t)

d = \frac{v_o + v_1}{2}(80)

1000 = 40(v_o + v_1)

also we know that

v_1 - v_o = a(80)

also we have

1000 = \frac{v_1 + v_2}{2}(120)

1000 = 60(v_1 + v_2)

now we can say

(v_2 + v_1) - (v_o + v_1) = \frac{50}{3} - \frac{50}{2}

also we know

v_2 - v_o = a(120 + 80)

-8.33 = 200 a

a = -0.042 m/s^2

Part b)

now we have

v_1 + v_o = 25

v_1 - v_o = (-0.042)(80)

v_1 = 10.83 m/s

so the starting velocity of the trip is

v_o = 25 - 10.83 = 14.17 m/s

now speed after t = 200 s is given as

v_2 = v_o + at

v_2 = 14.17 - (0.042)(200)

v_2 = 5.77 m/s

5 0
3 years ago
HELP PLS 100 POINTS TAKING TEST RN
s2008m [1.1K]

Answer:

I think he answer is C but I could be wrong

Explanation:

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How to understand that an inductor behaves like short circuit and capacitor like an open circuit in steady state in a network?
garik1379 [7]
It depends on the steady-state frequency. At zero frequency an inductor behaves like an open circuit. As the frequency increases, the inductor acts more like an open circuit and a capacitator acts more like a short circuit
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