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Leya [2.2K]
3 years ago
12

What would the electrostatic force be for two 0.005C charges 50m apart?

Physics
1 answer:
irakobra [83]3 years ago
3 0

Answer:

90 N

Explanation:

The electrostatic force between two charges is given by:

F=k\frac{q_1 q_2}{r^2}

where

k is the Coulomb's constant

q1, q2 are the two charges

r is the separation between the charges

In this problem we have

q1 = q2 = 0.005 C

r = 50 m

So the electrostatic force is

F=(9\cdot 10^9 N m^2 C^{-2})\frac{(0.005 C)^2}{(50 m)^2}=90 N

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Answer:

The answer is 4 pounds

Explanation:

The explanation is that 1 kilogram is equal to 2 pounds so multiply the kilogram with the 1 pound

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tatiyna

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3 years ago
Delilah does 170 Joules of work in 30 seconds. Adam does 260 Joules of work in 20 seconds. Who was more powerful?​
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6 0
3 years ago
A conducting loop in the form of a circle is placed perpendicular to a magnetic field of 0. 50 t. If the area of the loop decrea
Kisachek [45]

The induced emf in the loop is  -1500 μ V or  - 0.0015 V  .

According to the question

A conducting loop in the form of a circle is placed perpendicular to a magnetic field of 0. 50 t.  

i.e

Magnetic field (B) = 0. 50 T

Area of circle or loop = \pi r^{2}  

Now,

The area of the loop decreases at a rate of 3. 0 × 10⁻³ m/s

i.e

dA = 3. 0 × 10⁻³ meter²

dt = 1 sec  

As per the formula of Induced e.m.f in the loop

emf is dependent on number of turns of coil, shape of the coil, strength of magnet and speed with which magnet is moved. Emf is independent of resistivity of wire of the coil.

e=-B*\frac{dA}{dt}

where A is the area of the loop.

Now ,

Substituting the values in the formula

e=-B*\frac{dA}{dt}

e= - 0.50 *\frac{ 3 * 10^{-3}}{1}    

e = - 0.0015 V

OR

e = -1500 * 10⁻⁶ V

e =  -1500 μ V

Negative just signifies emf will such be induced that current induced will oppose change in magnetic field though it

To know more about induced emf here:

brainly.com/question/16764848

#SPJ4

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Answer:

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Read 2 more answers
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