Answer:2.45 m/s
Explanation:
Given
Launch velocity
launch angle
as the vertical velocity first decreasing to zero and then increases to original value so its avg is zero .
thus
What would the electrostatic force be for two 0.005C charges 50m apart?
1 answer:
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Answer:
a) The module's acceleration in a vertical takeoff from the Moon will be
b) Then we can say that a thrust of won't be able to lift off the module from the Earth because it's smaller than the module's weight (
).
Explanation:
a) During a vertical takeoff, the sum of the forces in the vertical axis will be equal to mass times the module's acceleration. In this this case, the thrust of the module's engines and the total module's weight are the only vertical forces. (In the Moon, the module's weight will be equal to its mass times the Moon's gravity acceleration)
Where:
thrust
module's mass
moon's gravity acceleration
module's acceleration during takeoff
Then, we can find the acceleration like this:
The module's acceleration in a vertical takeoff from the Moon will be
b) To takeoff, the module's engines must generate a thrust bigger than the module's weight, which will be its mass times the Earth's gravity acceleration.
Then we can say that a thrust of won't be able to lift off the module from the Earth because it's smaller than the module's weight (
).