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4 years ago

A system for specifying the precise of objects in space and time

1 answer:

german4 years ago

7 0

The answer is frame of reference ( system ).
Frame of reference is a physical concept related to state of motion.

hoped it helped!!

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A Plane has a takeoff speed of 150 m/s and requires 1500m to reach that speed. Determine the acceleration of the plane and the t

mars1129 [50]

Answer:

The acceleration of the plane and the time required to reach this speed is (a)= 7.5 $m/sec^2$ and time(t) = 20 seconds

Explanation:

Given data Initial velocity $(V_i)$ = 0

Final velocity ( $V_f$ ) = 150 m/second

Distance (d) = 1500 m

We have the formula, $\mathrm{V}_{\mathrm{f}}^{2}=\mathrm{V}_{\mathrm{i}}^{2}+2 \mathrm{ad}$

which gives $150^2$ = 0+2a(1500)

22500 = 3000 a

acceleration (a) = 7.5 $m/s^2$

$\mathrm{V}_{\mathrm{f}}=\mathrm{V}_{\mathrm{i}}+\mathrm{at}$

150 = 7.5 t

t= 150/7.5 = 20

t = 20 seconds.

5 0

3 years ago

Body types can be described as _____ (check all that are correct)Immersive Reader

rewona [7]

Apple, Pear, hourglass, bodybuilder, and rectangle.

4 0

3 years ago

A steel ball moves from a position of +125 meters to a position of -75 meters. This motion takes 90.0 seconds. What is the veloc

bonufazy [111]

Answer:

2.22m/s to the left

Explanation:

Given parameters:

Initial position = +125m

Final position = -75m

Motion time = 90s

Unknown:

Velocity of the steel ball = ?

Solution:

The velocity of the steel ball is given as the displacement divided by the time;

Velocity = $\frac{displacement}{time}$

The net displacement of the ball = 125- (-75) = 200m to the left

Input the parameters and solve for the velocity;

Velocity = $\frac{200}{90}$ = 2.22m/s to the left

3 0

4 years ago

Can someone help me?!!!!!

SOVA2 [1]

Answer:magnitude -5; angle 160°

Explanation:

Vector A is described as having magnitude 5 and angle -20°.

To get an equivalent vector, we either leave the magnitude at 5 and add 360° to the angle, or we reverse the magnitude to -5 and add 180° to the angle.

5 @ -20° = 5 @ 340°

5 @ -20° = -5 @ 160°

The third one is the answer.

8 0

4 years ago

A car speeds up from 18.54 m/s to 29.52 m/s in 13.84 s. The acceleration of the car is:

valkas [14]

Answer:

.7934 $m/s^{2}$

Explanation:

Acceleration = change in velocity / change in time

A = 10.98 $m/s$ / 13.84 $s$

A = .7934 $m/s^{2}$

5 0

3 years ago

Read 2 more answers