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4 years ago

12

A system for specifying the precise of objects in space and time

1 answer:

german4 years ago

7 0

The answer is frame of reference ( system ).
Frame of reference <span>is a physical concept related to state of motion.

hoped it helped!!</span>

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Which force controls the size of an atomic nucleus?

IrinaVladis [17]

Answer:

Strong nuclear force

Explanation:

6 0

2 years ago

A rock is suspended by a light string. When the rock is in air, the tension in the string is 51.9 N . When the rock is totally i

Luden [163]

Answer:

$\rho _{liquid}=1995.07kg/m^{3}$

Explanation:

When the rock is immersed in unknown liquid the forces that act on it are shown as under

1) Tension T by the string

2) Weight W of the rock

3) Force of buoyancy due to displaced liquid B

For equilibrium we have $T_{3}+B = W_{rock}$

$T_{3}+\rho _{Liquid}V_{rock}g$ = $W_{rock}.....(\alpha)$

When the rock is suspended in air for equilibrium we have

$T_{1}=W_{rock}....(\beta)$

When the rock is suspended in water for equilibrium we have

$T_{2}$ + $\rho _{water}V_{rock}g$ = $W_{rock}.....(\gamma)$

Using the given values of tension and solving α,β,γ simultaneously for $\rho _{Liquid}$ we get

$W_{rock}=51.9N\\31.6+1000\times V_{rock}\times g=51.9N\\\\11.4+\rho _{liquid}V_{rock}g=51.9N\\\\$

Solving for density of liquid we get

$\rho _{liquid}=\frac{51.9-11.4}{51.9-31.6}\times 1000$

$\rho _{liquid}=1995.07kg/m^{3}$

5 0

3 years ago

Is magnitude a<br> vector<br> scalars<br> both<br> neither

Doss [256]

Answer:

scalars

Explanation:

7 0

3 years ago

A scientific _______ is a principle that describes the behavior of a natural phenomenon. A. Model. B. law. C. theory d. Analysis

Jet001 [13]

A scientific law is a principle that describes the behavior of a natural phenomenon.

Example: Newton's Laws of Motion

3 0

3 years ago

Read 2 more answers

A rock dropped down a well takes 1.8 s to hit the water. How far below the top of the well is the surface of the water

Brut [27]

Answer: 15.87 m

From the equation of motion:

$s=ut+\frac{1}{2}at^2$

where, $s$ is the distance traveled, $u$ is the initial velocity, $a$ is the acceleration and $t$ is the time.

The rock free falls under gravity. Initial velocity, $u=0 m/s$ , $a=g=9.8m/s^2$

It took $t=1.8 s$ for rock to hit the water.

Substitute the values in the given equation:

$\Rightarrow s=0+\frac{1}{2}9.8m/s^2\times(1.8s)^2=15.87 m$

Hence, the water is 15.87 m below the top level of the well.

3 0

4 years ago