A system for specifying the precise of objects in space and time
1 answer:
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Answer:
1/9
Explanation:
<em>Newton’s Law of Universal Gravitation </em>
Objects with mass feel an attractive force that is proportional to their masses and inversely proportional to the square of the distance.
F = GMm/r²
where
F - the gravitatioal force in Newtons,
M and m -two masses in kilograms
r - the separation in meters.
G - the gravitational constant (6.674*10 ⁻¹¹ N (m/kg) ² )
Because of the magnitude of G , gravitational force is very small unless large masses are involved.
So according to above equation , when the masses are not changing , force is inversely propotional to the square of distance
F1 ∝ 1/r² ---------------(1)
F2 ∝ 1(3r)²
F2 ∝ 1/9r²--------------(2)
(2)/(1)
From their you get as the distance tripled, Force reduce by a factor of 9(3³)
for example , assume the distance get doubled ,Force reduce by a factor of 4 (2²)
Complete Question
A radio technician measures the frequency of an AM radio transmitter. The frequency is 14603 kHz . What is the frequency in megahertz? Write your answer as a decimal.
Answer:
The value is
Explanation:
From the question we are told that
The frequency is
Generally
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