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3 years ago

How many volts would it take to push 1 amp through a resistance of 1 ohm?

Physics

2 answers:

ELEN [110]3 years ago

5 0

V=I x R so V= 1 x 1 =1V

Diano4ka-milaya [45]3 years ago

4 0

Answer:

$1\; \rm V$ .

Explanation:

Ohm's Law give the following relationship between the potential $V$ across a conductor, the electrical resistance $R$ of that conductor, and the current $I$ through that conductor:

$V = I \, R$ .

It is given that the current through this conductor is $I = 1\; {\rm A}$ , and that the electrical resistance of this conductor is $R = 1\; \rm \Omega$ .

Note, that the unit of electrical resistance Ohm is a composite unit; $1\; {\rm \Omega} = 1\; {\rm V \cdot A^{-1}}$ (volts per ampere.)

Substitute the value of $I$ and $R$ into the equation $V = I \, R$ from Ohm's Law to find the potential across this conductor:

$\begin{aligned}V &= I \, R \\ &= 1\; {\rm A} \times 1\; {\rm \Omega} \\ &= 1\; {\rm A} \times 1\; {\rm V \cdot A^{-1}} \\ &= 1\; {\rm V}\end{aligned}$ .

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1. A toy car is marked to go at 0.5m/s, which of the following sets of

Lostsunrise [7]

Answer:

b. 0.6m/s, 0.7m/s, 0.61m/s, 0.62m/s

Explanation:

Precision of a measurement is the closeness of the experimental values to one another. Hence, experimental measurements are said to be precise if they are close to each other irrespective of how close they are to the accepted value. Precision can be determined by finding the range of each experimental value. The measurement with the LOWEST RANGE represents the MOST PRECISE.

Note: Range is the highest value - lowest value

Set A: 1.5 - 0.8 = 0.7

Set B: 0.7 - 0.6 = 0.1

Set C: 2.4 - 2.0 = 0.4

Set D: 3.1 - 2.9 = 0.2

Set B has the lowest range (0.1), hence, represent the most precise value.

8 0

3 years ago

When you go for a walk which of the following forces is paired with the force of friction on your shoe

Ann [662]

Answer:

static

Explanation:

static friction pushes in the direction you are walking.

7 0

3 years ago

What is the velocity (m/s) after 5 seconds of fall

gregori [183]

5 second fall starting at 0 m/s
ball strikes ground at a speed = 49 meters per second.

3 0

3 years ago

Ultrasonic images are obtained from the inside organs of our body. This process uses which property of sound wave?

Temka [501]

This question involves the concepts of echo, ultrasonic images, ultrasonic sound waves.

The process of ultrasonic images uses the "echo" property of the sound waves.

Echo is the property of the sound wave by the virtue of which the sound wave reflects back to the source of the sound after hitting a surface or an object.

Ultrasonic images are obtained from inside organs of our body. This process involves the use of ultrasonic sound waves that have a frequency greater than 20,000 Hz. These sound waves are out of the range of audible sound by the human ear. When these ultrasonic sound waves are sent in form of pulses into the human body by the use of probes, they reflect back from the tissues of different organs to the probe. The probe then records the reflection properties of these sound waves and displays them in form of an image, known as ultrasonic images.

Learn more about echo here:

brainly.com/question/14335186?referrer=searchResults

The attached picture shows the process of ultrasonic imaging.

4 0

2 years ago

What happened to the balloon when it was placed on the bottle with the baking soda and vinegar and why.

user100 [1]

Answer:

The ballon would be inflated. The reason is that the sodium bicarbonate in baking soda reacts with acetic acid in vinegar to produce gas.

Explanation:

The main component of baking soda is sodium bicarbonate, ${\rm Na_{2}CO_{3}}$ .

Vinegar is mostly a solution of acetic acid ${\rm CH_{3}COOH}$ in water.

Acids such as acetic acid react with carbonate salts. One of the products of such reactions is carbon dioxide ${\rm CO_{2}}$ , a gas.

In this question, when the acetic acid in vinegar reacts with sodium bicarbonate in the baking soda, the following reaction would occur:

$\begin{aligned}& {\rm Na_{2}CO_{3}}\, (aq) + 2\, {\rm CH_{3}COOH}\, (aq) \\ &\to 2\, {\rm CH_{3}COONa}\, (aq) + {\rm CO_{2}}\, (g)\end{aligned}$ .

The ${\rm CO_{2}}$ produced would then inflate the ballon placed on the opening of the bottle.

5 0

2 years ago