<img src="https://tex.z-dn.net/?f=%5Cbold%7BHeya...%7D" id="TexFormula1" title="\bold{Heya...}" alt="\bold{Heya...}" align="absm

All categories

2 years ago

iddle" class="latex-formula">
$\mathtt{9 \: - \: 3}$ ÷ $\mathtt{\frac{1}{3} \: 1 \: ?}$

Explain into your own words.

Thanks~

Mathematics

2 answers:

Bond [772]2 years ago

4 0

${ \qquad\qquad\huge\underline{{\sf Answer}}}$

Let's proceed according to Bodmas rule ~

$\qquad \sf \dashrightarrow \:9 - 3 \div \frac{1}{3} 1$

[ as 3 ÷ 1/3 = 3 × 3 = 9 ]

$\qquad \sf \dashrightarrow 9 - 9$

$\qquad \sf \dashrightarrow \:0$

So, by simplification we will get 0 as our result.

Ede4ka [16]2 years ago

4 0

Heyo!

I believe you mess up your fraction.

Let's do this step-by-step explanation.

$9-\frac{3}{1\frac{1}{3} }$

= $9-\frac{3}{\frac{4}{3} }$

= $9-\frac{9}{4}$

= $\frac{27}{4}$

= $6 \frac{3}{4}$

Answer:

$6 \frac{6}{4}$

Hopefully, this helps you!!

$HawtieNoya$

You might be interested in

Create two groups of cards with the SAME SUM using as many cards as possible using the numbers 8 7 6 2 1 3.

laila [671]

Answer:

Explained below.

Step-by-step explanation:

In this case we need to form two group of cards (consisting of any number of cards) having the same sum using the cards numbered as 8, 7, 6, 2, 1, 3.

The possible groups are as follows:

Group 1 Group 2 Sum

{8, 1} {7, 2} 9

{8, 2} {7, 3} 10

{8, 3} {7, 3, 1} 11

{8, 1, 3} {7, 3, 2} 12

{8, 2, 3} {7, 2, 1, 3} 13

{8, 3, 2, 1} {7, 6, 1} 14

And so on.

7 0

3 years ago

-3/5, 6/5, -12/5 What is the next term of the geometric sequence ?

raketka [301]

ANSWER:

24/5

STEP-BY-STEP EXPLANATION:

We have the following geometric sequence:

$s=-\frac{3}{5},\frac{6}{5},\frac{-12}{5}$

To know the following term, we must know the common ratio, like this:

$\begin{gathered} r=\frac{-\frac{12}{5}}{\frac{6}{5}}=-2 \\ r=\frac{\frac{6}{5}}{-\frac{3}{5}}=-2 \end{gathered}$

Therefore, the following term should be:

$-\frac{12}{5}\cdot-2=\frac{24}{5}$

8 0

1 year ago

Which table of values will generate this graph?

lesantik [10]

Answer:

2000, x37466

Step-by-step explanation:

3 0

3 years ago

Two faces of a six-sided die are painted red, two are painted blue, and two are painted yellow. The die is rolled three times, a

Keith_Richards [23]

Answer:

(a) 4/9

(b) 19/27

Step-by-step explanation:

The probability of each die turning up red or not turning red are:

$P(R) =\frac{2}{6}= \frac{1}{3}\\P(O) =\frac{4}{6}= \frac{2}{3}$

(a). Exactly one face up is red.

The odds of only the first die being red are:

$P(A=R) =\frac{1}{3} *\frac{2}{3}* \frac{2}{3} \\P(1=R) =\frac{4}{27}$

The same odds are valid for only the second or only the third die being red. Therefore, the probability that exactly one die turns up red is:

$P(R=1) = 3*\frac{4}{27}\\P(R=1) = \frac{4}{9}$

(b). At least one face up is red.

The probability that at least one die turns up red is the sum of the probabilities of exactly one (found in the previous item), two or all dice turning up red.

Following the same logic as in the previous item, the probability that exactly two dice turn up red is:

$P(R=2) = 3*(\frac{1}{3}*\frac{1}{3}*\frac{2}{3})\\P(R=2) = \frac{2}{9}$

The probability that all die turn up red is:

$P(R=3) = \frac{1}{3}*\frac{1}{3}*\frac{1}{3}\\P(R=3)=\frac{1}{27}$

Thus, the probability that at least one die turns up red is:

$P= P(R=1)+P(R=2)+P(R=3) = \frac{4}{9}+\frac{2}{9}+\frac{1}{27}\\P=\frac{19}{27}$

4 0

4 years ago

Sooooo, i spilled nail polish remover in my chrome book snd the keyboard is no longer working. also i'm on spring break tomorrow

k0ka [10]

Answer:

Oh snap TwT I wish U luck :3

Step-by-step explanation:

7 0

3 years ago