You will need to make the fractions have a common denominator in order to add or subtract. So 1/6 and 3/5 share a common denominator of 30, making 1/6 into 5/30 and 3/5 into 24/30. So 5/30 plus 24/30 equals 29/30. So, 30/30 (the whole) minus 29/30 equals 1/30, which is the amount of time spent on Sunday.
Answer:
what I think the answer is ×=-9
They are similar because there are 2 sides to them. they are different because an equation states that both sides are equal, but in an inequality, one side is either greater than, less than, greater than or equal to, or less than or equal to.
Answer:
<h2>It must be shown that both j(k(x)) and k(j(x)) equal x</h2>
Step-by-step explanation:
Given the function j(x) = 11.6 and k(x) = , to show that both equality functions are true, all we need to show is that both j(k(x)) and k(j(x)) equal x,
For j(k(x));
j(k(x)) = j[(ln x/11.6)]
j[(ln (x/11.6)] = 11.6e^{ln (x/11.6)}
j[(ln x/11.6)] = 11.6(x/11.6) (exponential function will cancel out the natural logarithm)
j[(ln x/11.6)] = 11.6 * x/11.6
j[(ln x/11.6)] = x
Hence j[k(x)] = x
Similarly for k[j(x)];
k[j(x)] = k[11.6e^x]
k[11.6e^x] = ln (11.6e^x/11.6)
k[11.6e^x] = ln(e^x)
exponential function will cancel out the natural logarithm leaving x
k[11.6e^x] = x
Hence k[j(x)] = x
From the calculations above, it can be seen that j[k(x)] = k[j(x)] = x, this shows that the functions j(x) = 11.6 and k(x) = are inverse functions.
Answer:
Max's team 5.75
Williams team 5.6
Max's team had better run rate