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3 years ago

Which list includes translucent objects only

Physics

1 answer:

Lunna [17]3 years ago

5 0

Objects that let in light and blurry images are translucent.

Translucent is a term that refers to an adjective. This characteristic is the property of an object to allow the passage of light, without allowing visibility with high clarity through it.

This term is often confused with transparency. However, they differ because a transparent object lets light through easily and allows you to see clearly through it.

According to the above, objects that allow light to pass through but do not allow clear vision are translucent.

Learn more in: brainly.com/question/10626808

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The "Garbage Project" at the University of Arizona reports that the amount of paper discarded by households per week is normally

Lorico [155]

Answer:

54%

Explanation:

We are given that

S.D=4.2 lb

Mean= $\mu=9.4 lb$

We have to find the percentage of household throw out at least 9 lb of paper a week.

Normal distribution formula :

$P(X\geq a)=P(z\geq \frac{a-\mu}{\sigma})$

We have a=9

$P(X\geq 9)=P(z\geq \frac{9-9.4}{4.2})=P(z\geq -0.1)$

$P(X\geq 9)=1-P(z$

$P(X\geq 9)=1-0.4602=0.5398\times 100=54$ %

Hence, the percentage of household throw out at least of paper a week=54%

7 0

3 years ago

I flow from a warmer object to a cooler object until both objects are the same temperature what am I?

jok3333 [9.3K]

HEAT flows from a warmer object to a cooler object until both objects are the same temperature. The answer is heat!

4 0

4 years ago

Read 2 more answers

You throw a ball upward from a window at a speed of 2.0 m/s. the ball accelerates at 9.8 m/s2. how fast is it moving when it hit

Nastasia [14]

At the point where the ball stops it has speed of 0 m/s. When it continues to fall in every meter it gets 9.8 m/s so you just put this :
9.8 m/s2 x 2.5 m = 24.5 m/s

6 0

4 years ago

A toy rocket is launched vertically from ground level (y = 0.00 m), at time t = 0.00 s. The rocket engine provides constant upwa

Ksju [112]

The toy rocket is launched vertically from ground level, at time t = 0.00 s. The rocket engine provides constant upward acceleration during the burn phase. At the instant of engine burnout, the rocket has risen to 72 m and acquired a velocity of 30 m/s. The rocket continues to rise in unpowered flight, reaches maximum height, and falls back to the ground with negligible air resistance.

The total energy of the rocket, which is a sum of its kinetic energy and potential energy, is constant.

At a height of 72 m with the rocket moving at 30 m/s, the total energy is m*9.8*72 + (1/2)*m*30^2 where m is the mass of the rocket.

At ground level, the total energy is 0*m*9.8 + (1/2)*m*v^2.

Equating the two gives: m*9.8*72 + (1/2)*m*30^2 = 0*m*9.8 + (1/2)*m*v^2

=> 9.8*72 + (1/2)*30^2 = (1/2)*v^2

=> v^2 = 11556/5

=> v = 48.07

<span>The velocity of the rocket when it impacts the ground is 48.07 m/s</span>

3 0

3 years ago

Pls help me i have to submit this due tomorrow :'D

aniked [119]

$\textsf {a) As there is no change in the initial and final positions, the displacement is}\\\textsf {equal to 0.}$

b) Finding total distance :

Distance travelled from 0 s to 5 s :

1/2 x 5 x 30 = 75 m

Distance travelled from 5 s to 10 s :

5 x 30 = 150 m

Distance travelled from 10 s to 15 s :

150 + 1/2 x 5 x 5
150 + 12.5 = 162.5 m

Distance travelled from 15 s to 20 s :

36 x 5 + 1/2 x 5 x 4
180 + 10 = 190 m

Distance travelled from 20 s to 25 s :

45 x 5 + 1/2 x 5 x 5
225 + 12.5 = 237.5 m

Distance travelled from 25 s to 30 s :

40 x 5 + 1/2 x 10 x 5
200 + 25 = 225 m

Distance travelled from 30 s to 35 s :

20 x 5 + 1/2 x 20 x 5
100 + 50 = 150 m

Distance travelled from 35 s to 40 s :

1/2 x 20 x 5
50 m

Total = 75 + 150 + 162.5 + 190 + 237.5 + 225 + 150 + 50

Total = 1240 m

c) velocity at t = 15 s

36/15
12/5
2.4 m/s

d) average velocity

0 m/s (as displacement is equal to 0)

e) average speed

1240/40
31 m/s

f) Part d uses displacement whereas part e uses distance

3 0

2 years ago