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Sladkaya [172]
3 years ago
10

5 . W h ic h o f th e fo l lo w in g is N O T a fu n d a m e n ta l S .I u n it? A . M e te r B . A m p e re C . K e lv in D . R

adian
Physics
2 answers:
Flauer [41]3 years ago
5 0

Answer:

D. Radian

Explanation:

hope it helps

serg [7]3 years ago
5 0

Explanation:

it is an AMPERE

because 1 AMPERE = CHARGE / TIME

WHICH INVOLVES 2 UNITS

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A force of 100 newtons is used to move an object a distance of 15 meters with a power of 25 watts. Find the
valentina_108 [34]


work is distance * force so 15*100=1500

and to find time you know power = diastance * force / time

so 25=15*100/t

25=1500/t

25/1500=t

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An electric hoist does 500 joules of work lifting a crate 2 meters. How
LenKa [72]
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A modern compact fluorescent lamp contains 1.4 mg of mercury (Hg). If each mercury atom in the lamp were to emit a single photon
Reika [66]

Answer:

A. 1.64 J

Explanation:

First of all, we need to find how many moles correspond to 1.4 mg of mercury. We have:

n=\frac{m}{M_m}

where

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m = 1.4 mg = 0.0014 g is the mass of mercury

Mm = 200.6 g/mol is the molar mass of mercury

Substituting, we find

n=\frac{0.0014 g}{200.6 g/mol}=7.0\cdot 10^{-6} mol

Now we have to find the number of atoms contained in this sample of mercury, which is given by:

N=n N_A

where

n is the number of moles

N_A=6.022\cdot 10^{23} mol^{-1} is the Avogadro number

Substituting,

N=(7.0\cdot 10^{-6} mol)(6.022\cdot 10^{23} mol^{-1})=4.22\cdot 10^{18} atoms

The energy emitted by each atom (the energy of one photon) is

E_1 = \frac{hc}{\lambda}

where

h is the Planck constant

c is the speed of light

\lambda=508 nm=5.08\cdot 10^{-7}nm is the wavelength

Substituting,

E_1 = \frac{(6.63\cdot 10^{-34} Js)(3\cdot 10^8 m/s)}{5.08\cdot 10^{-7} m}=3.92\cdot 10^{-19} J

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4 0
3 years ago
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AfilCa [17]
<span>2.5 m/s going upward.
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7 0
3 years ago
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