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2 years ago

The component of a regenerative vapor power cycle that permits only liquid to pass through to a region of lower pressure is a?

1 answer:

3 0

The component of a regenerative vapor power cycle that permits only liquid to pass through to a region of lower pressure is a Valve/trap.

<h3>What is vapor?</h3>

In physics, a substance in the gas phase at a temperature lower than its critical temperature is referred to as a vapor or vapor.
This means that the vapor can be condensed to a liquid by increasing the pressure on it without decreasing the temperature.
An aerosol is distinct from a vapor.
A suspension of minute liquid, solid, or both types of particles in a gas is known as an aerosol.

<h3>Why does vapor form?</h3>

Evaporation or sublimation are two processes that can be used to create it.
Unlike clouds, fog, or mist, which are only suspended drops of liquid water in the atmosphere, watevaporur is a gas and cannot be seen.
In the atmosphere, water vapor frequently exists below the boiling point.

Learn more about vapor here:

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You might be interested in

The development of various technologies led to many historic events. Use information from the Internet to describe one major his

11111nata11111 [884]

Answer:

1. Industrial revolution was initiated or borne through the production of Steel

2. World War 1 led to the development of Tanks

Explanation:

The production of Steel through the Bessemer Process in the middle of the nineteenth century was a major technological development that spurred the Industrial revolution. This invention led to the widespread use of steel in the production of many things including vehicles and airplanes.

During the First World War in 1914, soldiers found the use of just their armaments in battle as not so productive. This led to the development of Tanks in 1915 that would continue moving towards the enemy even when being shot at.

4 0

3 years ago

A rectangular conductor with a cross sectional area of 1.04 square millimeters (mm) ^2 has a resistance of 0.075 ohms. What woul

kogti [31]

Answer:

0.0375 ohms

Explanation:

The resistance of a material is the product of the resistivity of the material by the length of the material divided by its cross-section area.

Mathematically,

resistance= resistivity × length/area

In this case the resistivity of the material is the same, and the length is the same thus, assume a length of 1 unit, the cross-section area is the one changing

In applying the formula,

resistivity is r and length is l=1 unit, find the resistivity the material as;

resistance= resistivity * length /area

0.075=r*1/1.04

0.075=r*0.9615

0.075/0.9615 =r

r=0.078

use the r=0.078 , a length of 1 unit (assumed), and area of 2.08 mm² to find the new resistance

Resistance= resistivity * length /area

Resistance = 0.078*1/2.08

Resistance= 0.078 * 0.4807 = 0.0375 ohms

Point to note here is that the greater the cross-section area, the less the resistance.

4 0

3 years ago

The roof of a refrigerated truck compartment consists of a layer of foamed urethane insulation (t2 = 21 mm, ki = 0.026 W/m K) be

lakkis [162]

Answer:

Tso = 28.15°C

Explanation:

given data

t2 = 21 mm

ki = 0.026 W/m K

t1 = 9 mm

kp = 180 W/m K

length of the roof is L = 13 m

net solar radiation into the roof = 107 W/m²

temperature of the inner surface Ts,i = -4°C

air temperature is T[infinity] = 29°C

convective heat transfer coefficient h = 47 W/m² K

solution

As when energy on the outer surface at roof of a refrigerated truck that is balance as

Q = $\frac{T \infty - T si }{\frac{1}{hA}+\frac{t1}{AKp}+\frac{t2}{AKi}+\frac{t1}{aKp}}$ .....................1

Q = $\frac{T \infty - Tso}{\frac{1}{hA}}$ .....................2

now we compare both equation 1 and 2 and put here value

$\frac{29-(-4)}{\frac{1}{47}+\frac{2\times0.009}{180}+\frac{0.021}{0.026}} = \frac{29-Tso}{\frac{1}{47}}$

solve it and we get

Tso = 28.153113

so Tso = 28.15°C

3 0

3 years ago

What engineers call moment, scientists call

Svet_ta [14]

Answer:

yes

Explanation:

7 0

3 years ago

The 40-ft-long A-36 steel rails on a train track are laid with a small gap between them to allow for thermal expansion. Determin

vfiekz [6]

Answer:

Ф = 0.02838 ft

F = 1,032 N

Explanation:

To find out gap delta,

As it is case of free thermal expansion,

First we start with, some assumptions we have to made to solve this problem.

1. Thermal Expansion Coefficient of Steel is ∝= 6.45 ×10^(-6)

2. Modulas of elasticity for A-36 steel is E= 200 GPa

3. Area of rail is assumed to be unit area.

The gape required can be given by,

Ф = ∝ × ΔT × L ... where Ф= Gap Delta in ft

ΔT= Temperature rise in F

= 90- (-20)

= 110 F

Ф = 6.45 ×10^(-6) × 110 × 40

Ф = 28,380 × 10^(-6) ft

Ф = 0.02838 ft .... total gape required for expansion of steel rails

Stress induced in rails is given by,

σ = ∝ × ΔT × E

= 6.45 ×10^(-6) × 110 × 200

σ = 1,41,900 Pa

Now, let's find axial force in rails,

Here,we have to consider ΔT= 20 F.

As due to temperature change, axial force generated in rails can be find by,

F = A × ∝ × ΔT× E × L

F = 1 × 6.45 × 10^(-6) × 20 × 200 × 10^(-9) × 40

F = 25,800 × 40 × 10^(-3)

F = 10,32,000 × 10^(-3)

F= 1,032 N

Finally, due to temperature change, rail is subjected to axial force, axial stress.

8 0

3 years ago