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adelina 88 [10]
1 year ago
7

The component of a regenerative vapor power cycle that permits only liquid to pass through to a region of lower pressure is a?

Engineering
1 answer:
Zepler [3.9K]1 year ago
3 0

The component of a regenerative vapor power cycle that permits only liquid to pass through to a region of lower pressure is a Valve/trap.

<h3>What is vapor?</h3>
  • In physics, a substance in the gas phase at a temperature lower than its critical temperature is referred to as a vapor or vapor.
  • This means that the vapor can be condensed to a liquid by increasing the pressure on it without decreasing the temperature.
  • An aerosol is distinct from a vapor.
  • A suspension of minute liquid, solid, or both types of particles in a gas is known as an aerosol.
<h3>Why does vapor form?</h3>
  • Evaporation or sublimation are two processes that can be used to create it.
  • Unlike clouds, fog, or mist, which are only suspended drops of liquid water in the atmosphere, watevaporur is a gas and cannot be seen.
  • In the atmosphere, water vapor frequently exists below the boiling point.

Learn more about vapor here:

brainly.com/question/14578189

#SPJ4

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The specific gravity of a substance that has mass of 10 kg and occupies a volume of 0.02 m^3 is a) 0.5 b) 1.5 c) 2.5 d) 3.5 e) n
zhuklara [117]

Answer:

Specific gravity is 0.5 so option (a) is correct option

Explanation:

We have given mass of substance m =10 kg

Volume V=0.02m^3

Density of substance is given by Density\ d=\frac{mass}{volume}=\frac{10}{0.02}=500kg/m^3

Specific gravity is given by specific\ gravity=\frac{density\ of\ substance}{density\ f\ water}=\frac{500}{1000}=0.5

So option (a) is correct option

5 0
3 years ago
What is a magnitute?
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Answer:

Magnitude is a specific type of norm. Magnitude is what is known as the Euclidean norm. There are other norms, such as the Leibniz and the Chebychev norm.

Explanation:

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2 years ago
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Determine the total condensation rate of water vapor onto the front surface of a vertical plate that is 10 mm high and 1 m in th
castortr0y [4]

Answer:

Q =  63,827.5 W

Explanation:

Given:-

- The dimensions of plate A = ( 10 mm x 1 m )

- The fluid comes at T_sat , 1 atm.

- The surface temperature, T_s = 75°C  

Find:-

Determine the total condensation rate of water vapor onto the front surface of a vertical plate

Solution:-

- Assuming drop-wise condensation the heat transfer coefficient for water is given by Griffith's empirical relation for T_sat = 100°C.

                            h = 255,310 W /m^2.K

- The rate of condensation (Q) is given by Newton's cooling law:

                           Q = h*As*( T_sat - Ts )

                           Q = (255,310)*( 0.01*1)*( 100 - 75 )

                           Q =  63,827.5 W

8 0
3 years ago
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