Answer:
a) 14.285
b) 8.956
Explanation:
Given :
The combustion of the ethanol is with air
Air is 21% oxygen
and, 79% nitrogen
thus, for 1 O₂ we have (79/21)N₂
thus,
the stochiometric equation for the combustion is as:
C₂H₅OH + 3[O₂ + (79/21)N₂] ⇒ 2CO₂ + 3H₂O + 3 × (79/21)N₂
Now,
the molecular weight of the fuel (C₂H₅OH) = (2× 12) + (5 × 1) + 16 + 1 = 46 g/mol
Molecular weight of the air = (2 × 16) + ((79/21) × 28) = 137.33 g/mol
a) air/fuel ratio on a molar basis
we have
air-fuel ratio = moles of air / moles of fuel
or
air-fuel ratio = [3 × 1 + 3 × (79/21)] / 1 = 14.285
b) air/fuel ratio on a mass basis = Mass of air / mass of fuel
or
air/fuel ratio on a mass basis = (number of moles of air × molar mass of air) / (number of moles of fuel × molar mass of fuel)
on substituting the values, we have
air/fuel ratio on a mass basis = (3 × 137.33) / (1 × 46) = 8.956
The range of force exerted at the end of the rope is; 285.7 N to 1,000 N.
<h3>What is the Net horizontal force?</h3>
The net horizontal force of the cylinder when it is at equilibrium position can be found by applying Newton's second law of motion. Thus;
∑F = 0
F - μF_n = 0
We are given;
F_n = 5 kN = 5000 N
μ = 0.2
Thus;
F - 0.2(5,000) = 0
F - 1,000 = 0
F = 1,000 N
The strength of the applied force will be increasing as the number of turns of the rope increases. Thus;
Minimum force = Total force/number of turns of rope
Since rope is wrapped three and half times, then;
number of turns = 3.5
Thus;
minimum force = 1,000/3.5
minimum force = 285.7 N
Thus, the range of force exerted at the end of the rope is 285.7 N to 1,000 N.
Read more about net horizontal force at; brainly.com/question/26957287
Answer:
a) 2319.6 kPa
b) 0.027
c) 287.86 kg/m^3
Explanation:
The pressure is determined from table in the appendix for the given temperature:
P_220=2319.6 kPa
to calculate the quality we need to determine the masses of the vapor and the liquid and for that we need the respective specific volumes which can also be found in table.
m_liq = V_liq/α_liq
= 504.2 kg
m_vap = V_vap/α_vap
= 13.94 kg
q = m_vap/m_liq
= 0.027
Finally, the density is simply calculated as follows:
p = m_tot/V_tot
= 518.14 kg/1.8 m^3
= 287.86 kg/m^3
Answer:
I would say a level
Explanation:
A level is used as a horizontal reference line, which will tell if the building is leaning to one side, or if its up right. I may be wrong but this is the closest thing I can think of for this question.
