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2 years ago

Question 2

Engineering

1 answer:

ValentinkaMS [17]2 years ago

3 0

Answer:

r h ch y TC GG ch hh h h

No se

Explanation:

No seibibk h j h uh t t t

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Water flows at low speed through a circular tube with inside diameter of 2 in. A smoothly contoured body of 1.5 in. diameter is

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Answer:

Pressure = 11.38 psi

Force = 13.981 Ibf

Explanation:

Step by step solution is in the attached document.

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3 years ago

3.94 x 105) + (2.04 x 105)

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627.9 is the answer

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2 years ago

An aluminum block weighing 28 kg initially at 140°C is brought into contact with a block of iron weighing 36 kg at 60°C in an in

Anika [276]

Answer:

Equilibrium Temperature is 382.71 K

Total entropy is 0.228 kJ/K

Solution:

As per the question:

Mass of the Aluminium block, M = 28 kg

Initial temperature of aluminium, $T_{a} = 140^{\circ}C$ = 273 + 140 = 413 K

Mass of Iron block, m = 36 kg

Temperature for iron block, $T_{i} = 60^{\circ}C$ = 273 + 60 = 333 K

At 400 k

Specific heat of Aluminium, $C_{p} = 0.949\ kJ/kgK$

At room temperature

Specific heat of iron, $C_{p} = 0.45\ kJ/kgK$

Now,

To calculate the final equilibrium temperature:

Amount of heat loss by Aluminium = Amount of heat gain by Iron

$MC_{p}\Delta T = mC_{p}\Delta T$

$28\times 0.949(140 - T_{e}) = 36\times 0.45(T_{e} - 60)$

Thus

$T_{e} = 109.71^{\circ}C$ = 273 + 109.71 = 382.71 K

where

$T_{e}$ = Equilibrium temperature

Now,

To calculate the changer in entropy:

$\Delta s = \Delta s_{a} + \Delta s_{i}$

Now,

For Aluminium:

$\Delta s_{a} = MC_{p}ln\frac{T_{e}}{T_{i}}$

$\Delta s_{a} = 28\times 0.949\times ln\frac{382.71}{413} = - 2.025\ kJ/K$

For Iron:

$\Delta s_{i} = mC_{i}ln\frac{T_{e}}{T_{i}}$

$\Delta s_{a} = 36\times 0.45\times ln\frac{382.71}{333} = 2.253\ kJ/K$

Thus

$\Delta s =-2.025 + 2.253 = 0.228\ kJ/K$

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3 years ago

After a car is jump started, you must unclip the jumper cable clips______.

drek231 [11]

Answer:

The correct answer is;

In the reverse order you connected them

Explanation:

The process of jump starting a car is as follows;

1) Connect the positive or red clip to the dead battery

2) Connect the other end of the positive or red clip to the other end of the live battery in the donor car

3) Connect the negative or black clip to the negative terminal on the live battery

4) Connect the other end of the negative or black clip to the bare metal (without paint coating) on the donor car

5) Start and idle the donor car

6) Test to see if there is electric power in the dead car. If yes, then start the dead car

By disconnecting in the reverse other, that is by first removing the black or negative terminal from the dead vehicle chassis, prevents short circuiting the system with the rest of the metals parts in vehicle body when a metal makes contact while the positive terminal is removed and the negative terminal is still on the chassis.

8 0

3 years ago