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yKpoI14uk [10]
2 years ago
12

Question 2

Engineering
1 answer:
ValentinkaMS [17]2 years ago
3 0

Answer:

r h ch y TC GG ch hh h h

No se

Explanation:

No seibibk h j h uh t t t

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Explain two ways that anthropometric data could be useful when designing a tennis racket.
12345 [234]

Answer:

I hope it helps :)

Explanation:

It is useful to measure Height and Arm Span in tennis players. Body fat can be measured using the skinfold method. If this is not available, monitoring body weight changes would give an indication of body fat changes, assuming no

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3 years ago
The path taken to move items from their origin to their destination is known as which of the following?
mrs_skeptik [129]

Answer:d

Explanation:

7 0
2 years ago
1. When the pneumatic device was demonstrated, explain something that was different than what you expected.
Vera_Pavlovna [14]

Answer:

1. Effect of air pressure

2. air- powered wheel chair

3. Pneumatic valves

Explanation:

1. In any pneumatic device, the mipact of air pressure to produce the moving effect on an heavy object is unexpected.

2. pneumatice demultiplexer when air in comprressed tank is allowed released to cause movement of the  chair.

3. In industries, a pneumatic valve operates by force of air when actuated. A signal causes actuation of coil. When coil is energized, compressed high pressure air is allowe to enter in a small cylinder and cause operation of valve

5 0
3 years ago
Read 2 more answers
A strip ofmetal is originally 1.2m long. Itis stretched in three steps: first to a length of 1.6m, then to 2.2 m, and finally to
andreyandreev [35.5K]

Answer:

strains for the respective cases are

0.287

0.318

0.127

and for the entire process 0.733

Explanation:

The formula for the true strain is given as:

\epsilon =\ln \frac{l}{l_{o}}

Where

\epsilon = True strain

l= length of the member after deformation

l_{o} = original length of the member

<u>Now for the first case we have</u>

l= 1.6m

l_{o} = 1.2m

thus,

\epsilon =\ln \frac{1.6}{1.2}

\epsilon =0.287

<u>similarly for the second case we have</u>

l= 2.2m

l_{o} = 1.6m   (as the length is changing from 1.6m in this case)

thus,

\epsilon =\ln \frac{2.2}{1.6}

\epsilon =0.318

<u>Now for the third case</u>

l= 2.5m

l_{o} = 2.2m

thus,

\epsilon =\ln \frac{2.5}{2.2}

\epsilon =0.127

<u>Now the true strain for the entire process</u>

l=2.5m

l_{o} = 1.2m

thus,

\epsilon =\ln \frac{2.5}{1.2}

\epsilon =0.733

6 0
3 years ago
What standard feature is on all circular saws?
PtichkaEL [24]

What standard feature is on all circular saws?

4. All of the above

4 0
3 years ago
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