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prisoha [69]
3 years ago
10

When hermetic refrigerant motor-compressors are designed to operate continuously at currents greater than 156 percent of the rat

ed-load current, the nameplate is marked with _______ current
Engineering
1 answer:
ANEK [815]3 years ago
6 0

The nameplate of a hermetic refrigerant motor-compressor that is designed to operate continuously at currents greater than 156% of the rated-load current is marked with branch-circuit selection current.

<h3>What is a hermetic refrigerant motor-compressor?</h3>

A hermetic refrigerant motor-compressor can be defined as a mechanical device that is designed and developed by combining a compressor and motor in a single outer-welded steel shell.

Basically, a hermetic refrigerant motor-compressor is used in the following areas:

  • Household refrigerators
  • Freezers
  • Heat pumps
  • Air coolers
  • Water cooling equipment.
  • Small refrigeration equipment.

According to HSE, the nameplate of a hermetic refrigerant motor-compressor that is designed to operate continuously at currents greater than 156% of the rated-load current is marked with branch-circuit selection current, so as to ensure safety for end users and technicians.

Read more on refrigerants here: brainly.com/question/2928084

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PLEASE HELP, THANK YOU
Elena L [17]

Answer:

6,3,2,5,1,4 because they jst are

Explanation:

3 0
3 years ago
Please answer fast. With full step by step solution.​
lina2011 [118]

Let <em>f(z)</em> = (4<em>z </em>² + 2<em>z</em>) / (2<em>z </em>² - 3<em>z</em> + 1).

First, carry out the division:

<em>f(z)</em> = 2 + (8<em>z</em> - 2) / (2<em>z </em>² - 3<em>z</em> + 1)

Observe that

2<em>z </em>² - 3<em>z</em> + 1 = (2<em>z</em> - 1) (<em>z</em> - 1)

so you can separate the rational part of <em>f(z)</em> into partial fractions. We have

(8<em>z</em> - 2) / (2<em>z </em>² - 3<em>z</em> + 1) = <em>a</em> / (2<em>z</em> - 1) + <em>b</em> / (<em>z</em> - 1)

8<em>z</em> - 2 = <em>a</em> (<em>z</em> - 1) + <em>b</em> (2<em>z</em> - 1)

8<em>z</em> - 2 = (<em>a</em> + 2<em>b</em>) <em>z</em> - (<em>a</em> + <em>b</em>)

so that <em>a</em> + 2<em>b</em> = 8 and <em>a</em> + <em>b</em> = 2, yielding <em>a</em> = -4 and <em>b</em> = 6.

So we have

<em>f(z)</em> = 2 - 4 / (2<em>z</em> - 1) + 6 / (<em>z</em> - 1)

or

<em>f(z)</em> = 2 - (2/<em>z</em>) (1 / (1 - 1/(2<em>z</em>))) + (6/<em>z</em>) (1 / (1 - 1/<em>z</em>))

Recall that for |<em>z</em>| < 1, we have

\displaystyle\frac1{1-z}=\sum_{n=0}^\infty z^n

Replace <em>z</em> with 1/<em>z</em> to get

\displaystyle\frac1{1-\frac1z}=\sum_{n=0}^\infty z^{-n}

so that by substitution, we can write

\displaystyle f(z) = 2 - \frac2z \sum_{n=0}^\infty (2z)^{-n} + \frac6z \sum_{n=0}^\infty z^{-n}

Now condense <em>f(z)</em> into one series:

\displaystyle f(z) = 2 - \sum_{n=0}^\infty 2^{-n+1} z^{-(n+1)} + 6 \sum_{n=0}^\infty z^{-n-1}

\displaystyle f(z) = 2 - \sum_{n=0}^\infty \left(6+2^{-n+1}\right) z^{-(n+1)}

\displaystyle f(z) = 2 - \sum_{n=1}^\infty \left(6+2^{-(n-1)+1}\right) z^{-n}

\displaystyle f(z) = 2 - \sum_{n=1}^\infty \left(6+2^{2-n}\right) z^{-n}

So, the inverse <em>Z</em> transform of <em>f(z)</em> is \boxed{6+2^{2-n}}.

4 0
3 years ago
A three-point bending test is performed on a glass specimen having a rectangular cross section of height d = 5.4 mm (0.21 in.) a
Fudgin [204]

Answer:

5.21e-2mm

Explanation:

Please see attachment

8 0
3 years ago
What were some of the challenges to safety resulting from such radical airframe designs as highly swept wings, high wing loading
Andrew [12]
How to take off and land, stopping considerations (stopping distance), control system capability over a large speed range and flutter, and structural integrity for the wing platform and speed range.
8 0
3 years ago
Explain any five applications of computer modeling in beams.
coldgirl [10]

Answer:

Explain any five applications of computer modeling in beams.

Explanation:

7 0
3 years ago
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