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faust18 [17]
2 years ago
14

The height of a house is 52 ft. A tree beside the house is 7.5 ft more than twice as tall. What is the height, in feet, of the t

ree? HELP ME THEN ILL HELP U
Mathematics
1 answer:
krok68 [10]2 years ago
6 0

The height in feet of the tree is 111.5 ft.

<h3>How to find the height of a tree?</h3>

The height of a house is 52 ft.

A tree beside the house is 7.5 ft more than twice as tall.

The height of the tree is as follows:

let

x = height of the house

Therefore,

The height of the house = x = 52 ft

Hence,

height of the tree = 7.5 + 2x

height of the tree = 7.5 + 2(52)

height of the tree = 7.5 + 104

height of the tree = 111.5

height of the tree = 111.5 ft

learn more on height here: brainly.com/question/13868851

#SPJ1

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astraxan [27]
The scientific notation:  3.2 x10^2
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Noelle has 5/6 of a yard of purple ribbon and 9/10 of a yard of Pink ribbon. How mucho ribbon does se have altogether?
aev [14]
Well you need to find a common denominator which 30 is the closest one. 5/6 becomes 25/30, 9/10 becomes 27/30. 27/30+ 25/30 = 52/30. To simplify that you divide by 2 to get 26/15. It is no longer divisible to a whole number after that point.
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Stardust the unicorn, covered a distance of 50 miles on his first trip to the forest. On a later trip he travelled 300 miles whi
jok3333 [9.3K]

His new time compared with the old time was increased by factor of 2

<h3>Further explanation</h3>

Acceleration is rate of change of velocity.

\large {\boxed {a = \frac{v - u}{t} } }

\large {\boxed {d = \frac{v + u}{2}~t } }

<em>a = acceleration (m / s²)v = final velocity (m / s)</em>

<em>u = initial velocity (m / s)</em>

<em>t = time taken (s)</em>

<em>d = distance (m)</em>

Let us now tackle the problem!

This problem is about Kinematics.

In this problem we assume that the unicorn is moving at a constant speed so that the acceleration is zero.

<u>Given:</u>

first distance = d₁ = 50 miles

second distance = d₂ = 300 miles

v₂ = 3 v₁

<u>Unknown:</u>

t₂ : t₁ = ?

<u>Solution:</u>

To find his new time , we will use the following formula.

v_2 = 3 v_1

\frac{d_2}{t_2} = 3 \times \frac{d_1}{t_1}

\frac{300}{t_2} = 3 \times \frac{50}{t_1}

\frac{300}{t_2} = \frac{150}{t_1}

t_2 = \frac{300}{150} \times t_1

\large {\boxed {t_2 = 2 \times t_1} }

<h3>Learn more</h3>
  • Velocity of Runner : brainly.com/question/3813437
  • Kinetic Energy : brainly.com/question/692781
  • Acceleration : brainly.com/question/2283922
  • The Speed of Car : brainly.com/question/568302

<h3>Answer details</h3>

Grade: High School

Subject: Mathematics

Chapter: Kinematics

Keywords: Velocity , Driver , Car , Deceleration , Acceleration , Obstacle , Speed , Time , Rate , Sperm , Whale , Travel

8 0
3 years ago
Please help solve this SAT math problem. I have 4 more like these so need help with this so that I can solve the rest by myself.
stealth61 [152]

The notation just means

(f/g)(-4) = f(-4) / g(-4)

If f(x) = x² + 2 and g(x) = 1 - 3x, then

f(-4) = (-4)² + 2 = 16 + 2 = 18

g(-4) = 1 - 3 (-4) = 1 + 12 = 13

and so

(f/g)(-4) = 18/13

8 0
3 years ago
Need help with A and C <br><br>please :)
Dennis_Churaev [7]

First step: name the sides according to geometry standards, namely, the sides are named the same lowercase letter as the opposing angle. A revised diagram is shown.

Second step: we need to know the relationships of the trigonometric functions.

cosine(A)=cos(63) = adjacent / hypotenuse = AC/AB .................(1)

sine(A)=sin(63) = opposite / hypotenuse = CB/AB .......................(2)

We're given AB=7, so

using (1)

AC/AB=cos(63)

AC=ABcos(63)=7 cos(63) = 7*0.45399 = 3.17993 = 3.180 (to three dec. figures)

Using (2)

BC/AB=sin(63)

BC=ABsin(63) = 7 sin(63) = 7*0.89101 = 6.237 (to three dec. figures).


3 0
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