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1 year ago

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The height of a house is 52 ft. A tree beside the house is 7.5 ft more than twice as tall. What is the height, in feet, of the t

ree? HELP ME THEN ILL HELP U

1 answer:

krok68 [10]1 year ago

6 0

The height in feet of the tree is 111.5 ft.

<h3>How to find the height of a tree?</h3>

The height of a house is 52 ft.

A tree beside the house is 7.5 ft more than twice as tall.

The height of the tree is as follows:

let

x = height of the house

Therefore,

The height of the house = x = 52 ft

Hence,

height of the tree = 7.5 + 2x

height of the tree = 7.5 + 2(52)

height of the tree = 7.5 + 104

height of the tree = 111.5

height of the tree = 111.5 ft

learn more on height here: brainly.com/question/13868851

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Solve the system of equations.<br><br><br><br> −2x+5y =−35<br> 7x+2y =25

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Answer:

The equations have one solution at (5, -5).

Step-by-step explanation:

We are given a system of equations:

$\displaystyle{\left \{ {{-2x+5y=-35} \atop {7x+2y=25}} \right.}$

This system of equations can be solved in three different ways:

Graphing the equations (method used)
Substituting values into the equations
Eliminating variables from the equations

<u>Graphing the Equations</u>

We need to solve each equation and place it in slope-intercept form first. Slope-intercept form is $\text{y = mx + b}$ .

Equation 1 is $-2x+5y = -35$ . We need to isolate y.

$\displaystyle{-2x + 5y = -35}\\\\5y = 2x - 35\\\\\frac{5y}{5} = \frac{2x - 35}{5}\\\\y = \frac{2}{5}x - 7$

Equation 1 is now $y=\frac{2}{5}x-7$ .

Equation 2 also needs y to be isolated.

$\displaystyle{7x+2y=25}\\\\2y=-7x+25\\\\\frac{2y}{2}=\frac{-7x+25}{2}\\\\y = -\frac{7}{2}x + \frac{25}{2}$

Equation 2 is now $y=-\frac{7}{2}x+\frac{25}{2}$ .

Now, we can graph both of these using a data table and plotting points on the graph. If the two lines intersect at a point, this is a solution for the system of equations.

The table below has unsolved y-values - we need to insert the value of x and solve for y and input these values in the table.

$\begin{array}{|c|c|} \cline{1-2} \textbf{x} & \textbf{y} \\ \cline{1-2} 0 & a \\ \cline{1-2} 1 & b \\ \cline{1-2} 2 & c \\ \cline{1-2} 3 & d \\ \cline{1-2} 4 & e \\ \cline{1-2} 5 & f \\ \cline{1-2} \end{array}$

$\bullet \ \text{For x = 0,}$

$\displaystyle{y = \frac{2}{5}(0) - 7}\\\\y = 0 - 7\\\\y = -7$

$\bullet \ \text{For x = 1,}$

$\displaystyle{y=\frac{2}{5}(1)-7}\\\\y=\frac{2}{5}-7\\\\y = -\frac{33}{5}$

$\bullet \ \text{For x = 2,}$

$\displaystyle{y=\frac{2}{5}(2)-7}\\\\y = \frac{4}{5}-7\\\\y = -\frac{31}{5}$

$\bullet \ \text{For x = 3,}$

$\displaystyle{y=\frac{2}{5}(3)-7}\\\\y= \frac{6}{5}-7\\\\y=-\frac{29}{5}$

$\bullet \ \text{For x = 4,}$

$\displaystyle{y=\frac{2}{5}(4)-7}\\\\y = \frac{8}{5}-7\\\\y=-\frac{27}{5}$

$\bullet \ \text{For x = 5,}$

$\displaystyle{y=\frac{2}{5}(5)-7}\\\\y=2-7\\\\y=-5$

Now, we can place these values in our table.

$\begin{array}{|c|c|} \cline{1-2} \textbf{x} & \textbf{y} \\ \cline{1-2} 0 & -7 \\ \cline{1-2} 1 & -33/5 \\ \cline{1-2} 2 & -31/5 \\ \cline{1-2} 3 & -29/5 \\ \cline{1-2} 4 & -27/5 \\ \cline{1-2} 5 & -5 \\ \cline{1-2} \end{array}$

As we can see in our table, the rate of decrease is $-\frac{2}{5}$ . In case we need to determine more values, we can easily either replace x with a new value in the equation or just subtract $-\frac{2}{5}$ from the previous value.

For Equation 2, we need to use the same process. Equation 2 has been resolved to be $y=-\frac{7}{2}x+\frac{25}{2}$ . Therefore, we just use the same process as before to solve for the values.

$\bullet \ \text{For x = 0,}$

$\displaystyle{y=-\frac{7}{2}(0)+\frac{25}{2}}\\\\y = 0 + \frac{25}{2}\\\\y = \frac{25}{2}$

$\bullet \ \text{For x = 1,}$

$\displaystyle{y=-\frac{7}{2}(1)+\frac{25}{2}}\\\\y = -\frac{7}{2} + \frac{25}{2}\\\\y = 9$

$\bullet \ \text{For x = 2,}$

$\displaystyle{y=-\frac{7}{2}(2)+\frac{25}{2}}\\\\y = -7+\frac{25}{2}\\\\y = \frac{11}{2}$

$\bullet \ \text{For x = 3,}$

$\displaystyle{y=-\frac{7}{2}(3)+\frac{25}{2}}\\\\y = -\frac{21}{2}+\frac{25}{2}\\\\y = 2$

$\bullet \ \text{For x = 4,}$

$\displaystyle{y=-\frac{7}{2}(4)+\frac{25}{2}}\\\\y=-14+\frac{25}{2}\\\\y = -\frac{3}{2}$

$\bullet \ \text{For x = 5,}$

$\displaystyle{y=-\frac{7}{2}(5)+\frac{25}{2}}\\\\y = -\frac{35}{2}+\frac{25}{2}\\\\y = -5$

And now, we place these values into the table.

$\begin{array}{|c|c|} \cline{1-2} \textbf{x} & \textbf{y} \\ \cline{1-2} 0 & 25/2 \\ \cline{1-2} 1 & 9 \\ \cline{1-2} 2 & 11/2 \\ \cline{1-2} 3 & 2 \\ \cline{1-2} 4 & -3/2 \\ \cline{1-2} 5 & -5 \\ \cline{1-2} \end{array}$

When we compare our two tables, we can see that we have one similarity - the points are the same at x = 5.

Equation 1 Equation 2

$\begin{array}{|c|c|} \cline{1-2} \textbf{x} & \textbf{y} \\ \cline{1-2} 0 & -7 \\ \cline{1-2} 1 & -33/5 \\ \cline{1-2} 2 & -31/5 \\ \cline{1-2} 3 & -29/5 \\ \cline{1-2} 4 & -27/5 \\ \cline{1-2} 5 & -5 \\ \cline{1-2} \end{array}$ $\begin{array}{|c|c|} \cline{1-2} \textbf{x} & \textbf{y} \\ \cline{1-2} 0 & 25/2 \\ \cline{1-2} 1 & 9 \\ \cline{1-2} 2 & 11/2 \\ \cline{1-2} 3 & 2 \\ \cline{1-2} 4 & -3/2 \\ \cline{1-2} 5 & -5 \\ \cline{1-2} \end{array}$

Therefore, using this data, we have one solution at (5, -5).

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3 years ago

Which statement(s) is (are) correct?

Anna71 [15]

Answer:

<em>statements 3 and 4 are correct.</em>

Step-by-step explanation:

(1)

The probability of choosing cured pasta and bear= probability that the card is king.

Hence, The probability of choosing cured pasta and bear= $\dfrac{4}{52}=\dfrac{1}{13}$

Probability of choosing baked cucumber and lime mutton=probability that the card is 3.

as there are 4 cards that are '3'.

Hence Probability of choosing baked cucumber and lime mutton= $\dfrac{4}{52}=\dfrac{1}{13}$

as both the probabilities are equal.

Hence statement 1 is incorrect.

(2)

The probability of choosing gooseberry & passion fruit cheesecake= Probability taht the card is ace.

as there are 4 cards which are ace out of 52 cards.

Hence, The probability of choosing gooseberry & passion fruit cheesecake= $\dfrac{4}{52}=\dfrac{1}{13}$

probability of choosing poached fennel & lemon alligator=Probability that the card is a face card.

As there are 12 face cards out of 52 cards.

Hence, probability of choosing poached fennel & lemon alligator= $\dfrac{12}{52}=\dfrac{3}{13}$

Hence, the probability of choosing gooseberry and passion fruit cheesecake is smaller than the probability of choosing poached fennel & lemon alligator.

Hence statement 2 is false.

(3)

The probability of choosing a praline wafer=probability that the card is a diamond.

as there are 13 diamond cards out of 52 cards.

The probability of choosing a praline wafer= $\dfrac{13}{52}=\dfrac{1}{4}$

the probability of choosing poached fennel & lemon alligator=Probability that the card is a face card.

As there are 12 face cards out of 52 cards.

Hence, probability of choosing poached fennel & lemon alligator= $\dfrac{12}{52}=\dfrac{3}{13}$

Hence, The probability of choosing a praline wafer is greater than the probability of choosing poached fennel & lemon alligator.

Hence statement 3 is correct.

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The probability of choosing pressure-cooked mushroom & garlic chicken =probability that the card is red.

As there are 26 red cards out of 52 cards.

Hence,

The probability of choosing pressure-cooked mushroom & garlic chicken = $\dfrac{26}{52}=\dfrac{1}{2}$

probability of choosing an oven-baked apple & lavender calzone =probability that the card is black.

As there are 26 red cards out of 52 cards.

Hence, probability of choosing an oven-baked apple & lavender calzone= $\dfrac{26}{52}=\dfrac{1}{2}$

Hence, The probability of choosing pressure-cooked mushroom & garlic chicken and the probability of choosing an oven-baked apple & lavender calzone are the same.

Hence statement 4 is true.

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The probability of choosing pressure-cooked mushroom & garlic chicken =probability that the card is red.

As there are 26 red cards out of 52 cards.

Hence,

The probability of choosing pressure-cooked mushroom & garlic chicken = $\dfrac{26}{52}=\dfrac{1}{2}$

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as there are 13 diamond cards out of 52 cards.

The probability of choosing a praline wafer= $\dfrac{13}{52}=\dfrac{1}{4}$

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Step-by-step explanation:

In the function there's no value of x for which it is not defined thus domain is R.

Now a modulus will have always it's minimum value 0 thus minimum value of function is 0+3=3. And Max value of a modulus is infinite so infinite+3=infinite.

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