The cell potential at 250c for the following galvanic cell
pb(s)|pb2 (1.0m)||cu2 (1.0 x 10-4 m)|cu(s)
is 0.345V.
<h3>What is Electrolytic cell? </h3>
It is a device that is used for the conversion of the electrical energy of the redox reactions into a chemical energy.
<h3>What is redox reaction?</h3>
The reaction in which reduction and oxidation reaction both take place in the reaction is known as redox reaction.
<h3>
What is oxidation reaction?</h3>
Oxidation reaction are those reaction in which compound or substance looses its electron. In this type of reaction, oxidation state of an element increasing.
<h3>What is reduction reaction?</h3>
Reduction reaction are those reaction in which compound or substance accept the electron. In this type of reaction, oxidation state of an element goes on decreasing.
Reaction at cathode:
Cu+2 + 2e ------ Cu E°(anode) = -0. 126V
Reaction at anode:
pb ------- pb(+2) + 2e E°(cathode) = 0.337
E°cell = -0.126 -0.337
= -0.463V.
As we know that,
E cell = E°cell -0.059/2(log([cathode]/[anode])
= -0.463 - (0.059/2) × (-4)
= -0.463 + 0.118
= 0.345V
Thus, we concluded that the cell potential at 250c for the following galvanic cell
pb(s)|pb2 (1.0m)||cu2 (1.0 x 10-4 m)|cu(s)
is 0.345V.
learn more about redox reaction:
brainly.com/question/13293425
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