Solution :
Given :
Amount of anserine solution = 0.200 M
pH value is = 7.20
Preparation of 0.04 M solution of anserine from the 0.2 M solution.
0.2 M x 
= 0.04 M x 1000 ml
= 200 ml
So the 200 ml of 0.2 M anserine solution is required to prepare0.04 M of anserine.
0.1 M x = 0.04 x 1000 ml
= 400 ml
Therefore, 400 ml of HCl is needed.
Answer:
Phenylmethanethiol
Explanation:
Benzyl bromide is a compound from the toluene family with an alpha position substituent of bromine. When this compound (Benzyl bromide) reacts with sodium hydrogen sulfide, it yields a principal organic product called Phenylmethanethiol which is an alpha-toluenethiol that belongs to a group of aromatic compounds containing one monocyclic ring system comprising of benzene.
Answer:
Kf = [[Hg(NH₃)₄]²⁺] / [Hg²⁺] [NH₃]⁴
Last step: [Hg(NH₃)₃]²⁺ + NH₃(aq) ⇄ [Hg(NH₃)₄]²⁺(aq)
Explanation:
When the Hg²⁺ ion is in presence of ammonia molecules in an aqueous solution, the tetrahydrated complex is formed, following the equilibriums:
Hg²⁺(aq) + NH₃(aq) ⇄ [Hg(NH₃)]²⁺(aq) K₁
[Hg(NH₃)]²⁺ + NH₃(aq) ⇄ [Hg(NH₃)₂]²⁺(aq) K₂
[Hg(NH₃)₂]²⁺ + NH₃(aq) ⇄ [Hg(NH₃)₃]²⁺(aq) K₃
<em>[Hg(NH₃)₃]²⁺ + NH₃(aq) ⇄ [Hg(NH₃)₄]²⁺(aq) </em> K₄ → Last step.
Global reaction is:
Hg²⁺(aq) + 4 NH₃(aq) ⇄ [Hg(NH₃)₄]²⁺(aq)
And Kf is defined as:
<em>Kf = [[Hg(NH₃)₄]²⁺] / [Hg²⁺] [NH₃]⁴</em>
Answer:81.6%
Explanation:
Mass of CaCO3=4.010 g
Molar mass of CaCO3= 40+12+(16×3) = 100 g/mol.
Recall: number of moles(n)= mass÷ molar mass.
n=4.010÷100 = 0.0401 mol.
Molar mass of CaCl2 = 40+71= 111 g/mol.
Number of mol of CaCl2 = 5.455÷111= 0.04914 g/mol.
Mass of CaCl2 = 0.0401 × 111 = 4.4511 g of CaCl2.
Percent by mass of CaCl2 = (4.4511÷5.455) × 100
= 0.815967 ×100 = 81.5967%
Approximately; 81.6%.
Hydration number is 9
Given:
molar mass of na2so4•nh2o = 304.04 g/mol
To Find:
hydration number 'n'
Solution: hydration number is the number of molecules of water with which an ion can combine in an aqueous solution of given concentration.
Atomic mass of Na = 23g
S = 32g
0 = 16g
H = 1g
Molar mass of the compound is evaluated as:
2(23) +32 + 4(16) + n[2(1) +16] = 304.04
46 +32 +64 +18n = 304.04
142 +18n = 304.04
18n = 304.04 - 142
18n = 162.04
n = 9
So, hydration number is 9
Learn more about Hydration number here:
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