Answer:
12 more oxygen
Explanation:
An atom is the smallest particles that can take part in a chemical reaction
The given compounds are:
3Mg₃(PO₄)₂
Number of oxygen atoms = 3[2 x 4] = 24 oxygen atoms
For;
4Al₂O₃;
Number of oxygen atoms = 4 x 3 = 12 oxygen atoms
In 3Mg₃(PO₄)₂ , there are 24 - 12 = 12 more oxygen atoms than in 4Al₂O₃;
So the question ask to calculate the over all equation for a certain element and the following are
- over all equation - FE(OH)3+3NH4CI
- over all ionic equation - e(OH)3 (s) & 3 NH4+ (aq) & 3Cl- (aq) - net ionic equation - Fe+3+3OH-+3NH$++3CI-
MAl₂(SO₄)₃·xH₂O:
(mAl×2) + (mS×3) + (mO×12) + (mH₂O×x)
(27×2)+(32×3)+(16×12)+(x×18) = 342 + 18x [g]
mAl₂: 27×2 = 54 [g]
54g ---------- 13,63%
342+18x ---- 100%
0,1363(342+18x) = 54
46,6146 + 2,4534x = 54
2,4534x = 7,3854
x ≈ 3
>>> Al₂(SO₄)₃·3H₂O <<<<
:)
Answer:
See explanation
Explanation:
Anode;
Sn(s) ------> Sn^2+(aq) + 2e
Cathode;
Mn^2+(aq) + 2e ------> Mn(s)
The minimum voltage required to drive the reaction is the cell voltage. The cell voltage is obtained from;
E°cell= E°cathode - E°anode
E°cell= -1.19 - (-0.14)
E°cell= -1.05 V
