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Fiesta28 [93]
3 years ago
11

The number of moles of chloride ions in 250 ml of 4.00 M MgCL2

Chemistry
1 answer:
Tamiku [17]3 years ago
6 0
If you mean 4 moles per litre then:
In 1 litre there is 4 moles, therefore in .25 litres there is 1 mole.
1 mole of Magnesium Chloride would produce 2 moles of chloride ions (MgCl2 can also be written as Mg1Cl2, which dissolves to produce 1Mg(2+) and 2Cl(1-) ions: a 1:2 ratio)

So the answer is 2 moles of Chloride ions.        
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The correct answer is option a, that is, it gets broken down.  

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Which statement concerning how geologists locate an earthquake's epicenter are accurate? check all that apply
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Answer:

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Two systems with heat capacities 19.9 J mol-1 K-1 and 28.2 ] mol 1 K-1 respectively interact thermally and come to an equilibriu
MAVERICK [17]

Answer : The initial temperature of system 2 is, 19.415^oC

Explanation :

In this problem we assumed that the total energy of the combined systems remains constant.

-q_1=q_2

m\times c_1\times (T_f-T_1)=-m\times c_2\times (T_f-T_2)

The mass remains same.

where,

C_1 = heat capacity of system 1 = 19.9 J/mole.K

C_2 = heat capacity of system 2 = 28.2 J/mole.K

T_f = final temperature of system = 30^oC=273+30=303K

T_1 = initial temperature of system 1 = 45^oC=273+45=318K

T_2 = initial temperature of system 2 = ?

Now put all the given values in the above formula, we get

-19.9J/mole.K\times (303-318)K=28.2J/mole.K\times (303-T_2)K

T_2=292.415K

T_2=292.415-273=19.415^oC

Therefore, the initial temperature of system 2 is, 19.415^oC

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If the density of a liquid is 20g/mL and the volume is 70mL, what is the mass?
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Answer:

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harkovskaia [24]

The volume of Muriatic acid needed is 199ml.

<h3>What is concentration?</h3>
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  • Any type of chemical mixture can be referred to by the term "concentration," however solutes and solvents in solutions are most usually mentioned.
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  • Subtract the solute's mass from the total volume of the solution. Using m as the solute's mass and V as the total volume of the solution, write out the equation C = m/V.
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