compute the mean and variance of the following discrete probability distribution. (round your answers to 2 decimal places.) x p(
1 answer:
The determined value of mean µ is 1.3 and variance σ² is 0.81.
What is mean and variance?
- A measurement of central dispersion is the mean and variance. The average of a group of numbers is known as the mean.
- The variance is calculated as the square root of the variance.
- We can determine how the data we are collecting for observation are dispersed and distributed by looking at central dispersion.
The table is attached as an image for reference.
Mean µ = ∑X P(X)
µ = 1.3
Variance (σ² ) = ∑ X² P(X)- (µ)²
= 2.5-(1.3)²
(σ² ) = 0.81
The determined value of mean µ is 1.3 and variance σ² is 0.81.
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Answer:
C. 469 in²
Step-by-step explanation:
The net of the object is a rectangle that is 28 inches long and 14 inches wide. Its area is 392 square inches.
In addition, there are two triangles with base 11 inches and height 7 inches. Together, they have the area of a rectangle 7 by 11, or 77 square inches.
The total surface area of the prism is then ...
(392 + 77) in² = 469 in²
_____
The area of a rectangle is the product of its length and width.
The area of a triangle is half the product of its base and height. So, the area of two identical triangles is the product of their base and height.
_____
<em>Comment on the geometry</em>
This geometry cannot exist as shown. The height of the triangular face is closer to 6.454 inches than to 7 inches.
