compute the mean and variance of the following discrete probability distribution. (round your answers to 2 decimal places.) x p(
1 answer:
The determined value of mean µ is 1.3 and variance σ² is 0.81.
What is mean and variance?
- A measurement of central dispersion is the mean and variance. The average of a group of numbers is known as the mean.
- The variance is calculated as the square root of the variance.
- We can determine how the data we are collecting for observation are dispersed and distributed by looking at central dispersion.
The table is attached as an image for reference.
Mean µ = ∑X P(X)
µ = 1.3
Variance (σ² ) = ∑ X² P(X)- (µ)²
= 2.5-(1.3)²
(σ² ) = 0.81
The determined value of mean µ is 1.3 and variance σ² is 0.81.
Learn more about mean and variance here:
#SPJ4
You might be interested in
The attached graph represents the location of the pH values 0 and 1
<h3>How to plot the points?</h3>The given parameters are:
pH value 0 = (1, 0)
pH value 1 = (0.1, 1)
This means that we plot a point at the coordinate (1, 0) and another point at the coordinate (0.1, 1).
See attachment for the graph
Read more about graphs at:
#SPJ1
<u>Complete question</u>
The pH value is 0 at (1, 0) and 1 at (0.1, 1).
Using desmos
A. Locate, plot, and label on your graph where the pH value is 0.1
B. Locate, plot, and label on your graph where the pH value is 1.
