Answer:
im not sure the answer tho- just trying
compute the mean and variance of the following discrete probability distribution. (round your answers to 2 decimal places.) x p(
1 answer:
The determined value of mean µ is 1.3 and variance σ² is 0.81.
What is mean and variance?
- A measurement of central dispersion is the mean and variance. The average of a group of numbers is known as the mean.
- The variance is calculated as the square root of the variance.
- We can determine how the data we are collecting for observation are dispersed and distributed by looking at central dispersion.
The table is attached as an image for reference.
Mean µ = ∑X P(X)
µ = 1.3
Variance (σ² ) = ∑ X² P(X)- (µ)²
= 2.5-(1.3)²
(σ² ) = 0.81
The determined value of mean µ is 1.3 and variance σ² is 0.81.
Learn more about mean and variance here:
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