Answer:
Step-by-step explanation:
Consider this option:
1. area_rombus=a*h, where a=6 - the length of the side, h - height.
h=area_rombus/a.
2. area_sq=a², where a=6 - the length of the square.
area_sq=36, area_rombus=4/5 *36=28.8.
3. according to the item 1 h=area_rombus/a=28.8/6=4.8.
answer: 4.8
Answer:
3x³ - 2x² + 1 = 0
Step-by-step explanation:
By definition, a quadratic equation cannot have an exponent higher than 2.
Ok, so what we want to do here is first remove the repeating decimal.
x=2.16 repeating
10x=21.6 repeating
100x=216.6 repeating
Subtract 10x=21.6 repeating from 100x=216.6 repeating. This will get rid of the repeating numbers.
100x=216.6 repeating
-10x=21.6 repeating
__________________
90x=195
Divide both sides by 90.
x=195/90
Now you can simplify that into 13/6.
F ( x ) = 3 sim x + 3 cos x
f ` ( x ) = 3 cos x - 3 sin x
f `` ( x ) = - 3 sin x - 3 cos x = - 3 ( sin x + cos x )
The inflection points:
- 3 ( sin x + cos x ) = 0
sin x + cos x = 0
sin x = - cos x / : cos x
tan x = - 1
x 1 = 3π / 4
x 2 = 7π / 4
The function is concave up when f``(x) > 0
- 3( sin x+ cos x ) > 0
sin x + cos x < 0
tan x < - 1
f is concave up for:
x ∈ ( π/2, 3π/4 ) ∪ ( 3π/2, 7π/4)
f is concave down for:
x ∈ ( 0, π/2 ) ∪ ( 3π / 4, 3π/2 ) ∪ ( 7π / 4, 2 π ).
