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2 years ago

Refrigerant entering the compressor of a refrigeration system is a:________

Physics

1 answer:

schepotkina [342]2 years ago

7 0

Refrigerant entering the compressor of a refrigeration system is sub-cooled liquid

The liquid refrigerant is sub-cooled to ensure that only liquid and not the vapour enters the throttling valve. In a refrigeration system, the superheating decreases COP increase refrigerating effect but increasing amount of work done. The coefficient of performance or COP (sometimes CP or CoP) of a heat pump, refrigerator or air conditioning system is a ratio of useful heating or cooling provided to work (energy) required. Higher COPs equate to higher efficiency, lower energy (power) consumption and thus lower operating costs.

Learn more about sub-cooled here:

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Mike has a mass of 97 kg. He jumps out of a perfectly good airplane that is 2000 m above the ground. After he falls 1000 m, when

Ne4ueva [31]

Answer:

a) fr = 224.3 N , b) fr = 224.3 N , c) v = 198.0 m/s

Explanation:

a) For this exercise let's start by calculating the acceleration in the fall

v² = v₀² - 2 a (y-y₀)

When it jumps the initial vertical speed is zero

a = -v² / 2 (y-y₀)

a = -68 2/2 (1000-2000)

a = 2,312 m / s²

Let's use the second net law to enter the average friction force

fr = m a

fr = 97 2,312

fr = 224.3 N

b) let's look for acceleration

v² = v₀² - 2 a y

a = (v² –v₀²) / 2 (y-y₀)

a = (4² - 68²) / 2 (0-1000)

a = 2,304 m / s²

fr = m a

fr = 97 2,304

fr = 223.5 N

c) the speed of the wallet is searched with kinematics

v² = v₀² - 2 g (y-y₀)

v = √ (0-2 9.8 (0-2000))

v = 198.0 m/s

4 0

3 years ago

A 1,100 kg car is traveling initially 20 m/s when the brakes are applied. The brakes apply a constant force while bringing the c

Natalka [10]

Answer:

Work done = -220,000 Joules.

Explanation:

<u>Given the following data;</u>

Mass = 1100kg

Initial velocity = 20m/s

To find workdone, we would calculate the kinetic energy possessed by the car.

Kinetic energy can be defined as an energy possessed by an object or body due to its motion.

Mathematically, kinetic energy is given by the formula;

$K.E = \frac{1}{2}MV^{2}$

Where,

K.E represents kinetic energy measured in Joules.

M represents mass measured in kilograms.

V represents velocity measured in metres per seconds square.

Substituting into the equation, we have;

$K.E = \frac{1}{2}*1100*20^{2}$

$K.E = 550*400$

K.E = 220,000J

Therefore, the workdone to bring the car to rest would be -220,000 Joules because the braking force is working to oppose the motion of the car.

4 0

3 years ago

Three charges are on a line. A positive charge is on the far left labeled q Subscript 1 baseline positive 6 Coulombs. The second

tiny-mole [99]

Answer:

–1.1 × 10^11 N

Explanation:

I did the assignment

4 0

3 years ago

A dime is placed in front of a concave mirror that has a radius of curvature R = 0.40 m. The image of the dime is inverted and t

andrew11 [14]

Answer:

distance between the dime and the mirror, u = 0.30 m

Given:

Radius of curvature, r = 0.40 m

magnification, m = - 2 (since,inverted image)

Solution:

Focal length is half the radius of curvature, f = $\frac{r}{2}$

f = $\frac{0.40}{2} = 0.20 m$

Now,

m = - $\frac{v}{u}$

- 2 = - $\frac{v}{u}$

$\frac{v}{u}$ = 2 (2)

Now, by lens maker formula:

$\frac{1}{f} = \frac{1}{u} + \frac{1}{v}$

$\frac{1}{v} = \frac{1}{f} - \frac{1}{u}$

v = $\frac{uf}{u - f}$ (3)

From eqn (2):

v = 2u

put v = 2u in eqn (3):

2u = $\frac{uf}{u - f}$

2 = $\frac{f}{u - f}$

2(u - 0.20) = 0.20

u = 0.30 m

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3 years ago

prepara un escrito en el que resumas las ideas principales sobre la evolución de los modelos atómicos

Dvinal [7]

Mexico Mexico language to is the answer to the question

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3 years ago