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2 years ago

What are at least 3 examples of sublimation?

Physics

2 answers:

Step2247 [10]2 years ago

5 0

Answer:

dry ice, air fresheners, polar evaporation, arsenic treatment

barxatty [35]2 years ago

3 0

Dry ice, ice crystals inside boxes of frozen food, snow under certain conditions, iodine crystals, Arsenic, bathroom fresheners,

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A copper wire (density equal to 8900 kg / m3) 0.3 mm in diameter "floats" due to the force of the earth's magnetic field, which

Andrews [41]

Answer: $I=112.094\ A$

Explanation:

Given

density $\rho =8900\ kg/m^3$

diameter $d=0.3\ mm$

Magnetic field $B=5.5\times 10^{-5}\ T$

Force on the current carrying conductor placed in a magnetic field

$F=BIL\sin \theta$

where L=length of conductor

$\theta$ =angle between magnetic field and current

If the wire is floating then weight must be balanced by weight of wire

$Weight=mg=\rho ALg$

Therefore

$\rho ALg=BIL\times \sin 90$

$8900\times \frac{\pi}{4}(0.3\times 10^{-3})^2L\times 9.8=5.5\times 10^{-5}\times I\times L$

$I=\frac{8900\times \pi\times 9\times 10^{-8}\times 9.8}{4\times 5.5\times 10^{-5}}$

$I=112.094\ A$

5 0

2 years ago

It turns out that Mercury and Mars have the same gravity as one another – that is, you would weigh the same on the surface of Me

Tamiku [17]

Answer:

Explanation:

The value of acceleration due to gravity of mars is same as that the value of acceleration due to gravity of Mercury.

The value of acceleration due to gravity of a planet depends on its mass and the radius.

The formula for the acceleration due to gravity is given by

$g=\frac{GM}{R^{2}}$

Where, M be the mass of the planet, R be the radius of the planet.

As according to the question, the value of acceleration due to gravity for Mercury is same as that of Mars.

$\frac{GM_{mercury}}{R_{mercury}^{2}}=\frac{GM_{mars}}{R_{mars}^{2}}$

$\frac{M_{mercury}}{R_{mercury}^{2}}=\frac{M_{mars}}{R_{mars}^{2}}$

As teh radius of Mercury is small, and acceleration due to gravity is same, it is possible because the mass of Mercury is more than the mass of Mars.

4 0

3 years ago

For an object moving with constant negative acceleration, draw the following:

Tcecarenko [31]

Answer:

Kindly find the graphs attached

Explanation:

For figure 1: There is a steady increase in the position of the object as time increases. This is because despite the negative acceleration (deceleration), the object continues to move and cover more ground as time goes by.

<em>The straight line graph is observed because the acceleration is constant and not varying.</em>

For Figure 2: The graph of velocity vs time will have an inverted nature. This is because since the object is decelerating, it is reducing in its velocity as time goes by (increases). <em>This is also in a straight line since the deceleration is constant.</em>

3 0

3 years ago

Astronaut Rob leaves Earth in a spaceship at a speed of 0.960crelative to an observer onEarth. Rob's destination is a star syste

Slav-nsk [51]

To solve this problem we will use the mathematical definition of the light years in metric terms, from there, through the kinematic equations of motion we will find the distance traveled as a function of the speed in proportion to the elapsed time. Therefore we have to

$1Ly =9.4605284*10^{15}m \rightarrow 'Ly'$ means Light Year