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3 years ago

What are at least 3 examples of sublimation?

Physics

2 answers:

Step2247 [10]3 years ago

5 0

Answer:

dry ice, air fresheners, polar evaporation, arsenic treatment

barxatty [35]3 years ago

3 0

Dry ice, ice crystals inside boxes of frozen food, snow under certain conditions, iodine crystals, Arsenic, bathroom fresheners,

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The latent heat of vaporization of a substance is the amount of energy associated with doing which of the following to 1 kg of t

mr Goodwill [35]

Converting it from liquid to gas

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3 years ago

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A weightlifter deadlifts a 300 kg weight. If the weightlifter has a mass of 100 kg, what is the force acting on his legs?

sergeinik [125]

300 + 100 = 400

(Im not 100% sure of this answer)

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3 years ago

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A non uniform rod has mass

Doss [256]

Answer:

$r_{cm} = L/3$

Explanation:

Mass: M, Length: L.

$\sigma (x) = b(L-x)$

The formula that gives center of mass is

$\vec{r}_{cm} = \frac{m_1\vec{r}_1 + m_2\vec{r}_2 + ...}{m_1 + m_2 + ...} = \frac{\Sigma m_i \vec{r}_i}{\Sigma m_i}$

In the case of a non-uniform mass density, this formula converts to

$\vec{r}_{cm} = \frac{\int\limits^L_0 {x\sigma(x)} \, dx }{\int\limits^L_0 {\sigma(x)} \, dx }$

where the denominator is the total mass and the nominator is the mass times position of each point on the rod.

We have to integrate the mass density over the total rod in order to find the total mass. Likewise, we have to integrate the center of mass of each point (xσ(x)) over the total rod. And if we divide the integrated center of mass to the total mass, we find the center of mass of the rod:

$\vec{r}_{cm} = \frac{\int\limits^L_0 {x\sigma(x)} \, dx }{\int\limits^L_0 {\sigma(x)} \, dx } = \frac{\int\limits^L_0 {xb(L-x)} \, dx }{\int\limits^L_0 {b(L-x)} \, dx } = \frac{b\int\limits^L_0{(xL - x^2)} \, dx }{b\int\limits^L_0 {(L-x)} \, dx } = \frac{\frac{x^2L}{2} - \frac{x^3}{3}}{Lx - \frac{x^2}{2}}\left \{ {{x=L} \atop {x=0}} \right.$

Here x's are cancelled. Otherwise, the denominator would be zero.

$r_{cm} = \frac{\frac{xL}{2}-\frac{x^2}{3}}{L-\frac{x}{2}}\left \{ {{x=L} \atop {x=0}} \right. = \frac{\frac{L^2}{2}-\frac{L^2}{3}}{L-\frac{L}{2}} = \frac{\frac{L^2}{6}}{\frac{L}{2}} = \frac{L}{3}$

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3 years ago

The weight of a body floating in a liquid is

djverab [1.8K]

Answer:

The apparent weight is the weight of the body minus the weight of the liquid displaced. The body will float only when both the weights are same. In this case, the given body of weight W is floating and hence the apparent weight is zero.

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3 years ago

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A small diameter lead ball and a large diameter rubber ball are dropped from a tower. The balls hit the ground at the same time.

Gekata [30.6K]

Answer:

A) No conclusion can be drawn without more information about the two balls.

Explanation:

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4 years ago

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