Answer:
=Y2-10Y
We move all terms to the left:
-(Y2-10Y)=0
We add all the numbers together, and all the variables
-(+Y^2-10Y)=0
We get rid of parentheses
-Y^2+10Y=0
We add all the numbers together, and all the variables
-1Y^2+10Y=0
a = -1; b = 10; c = 0;
Δ = b2-4ac
Δ = 102-4·(-1)·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
Y1=−b−Δ√2aY2=−b+Δ√2a
Δ‾‾√=100‾‾‾‾√=10
Y1=−b−Δ√2a=−(10)−102∗−1=−20−2=+10
Y2=−b+Δ√2a=−(10)+102∗−1=0−2=0
Your answer is -206 just subtract
Answer:
flipping heads on a coin is a 1/2 chance, and multiples of three are 3 and 6, which is 1/3, thus, 1/2×1/3=1/5 there is a 1/5 chance Erwin will flip heads and roll a multiple of 3.
Answer:
Hi, I believe the answer to this problem would be A.
Let me know if I'm wrong though...
Answer:
Matched pairs design
Step-by-step explanation:
Looking at the options;
-It's not a completely randomized design because a randomized design will assign all individuals to a group which in this case it doesn't.
- It's not a randomized block design because randomized block design will group the subjects in question into 2 or more blocks which have a common characteristic and will then randomly assign subjects in each of the blocks.
-It's a matched pair because every individual/subject undergoes measurements both before and after being treated with the drugs.
Thus, the correct option is matched pairs design.
