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1 year ago

Tysm for the help! <3

Mathematics

1 answer:

Blizzard [7]1 year ago

7 0

By using the given graph:

When x = -2, the value of the function is f(-2) = 1
When x = -0.5, the value of the function is f(-0.5) = 0.75
When x = 0, the value of the function is f(0) = 1.25
When x = 2.5, the value of the function is f(2.5) = 3
When x = 6, the value of the function is f(6) = 0

<h3></h3><h3>How to use the graph to find the values of the function?</h3>

Suppose that we want to find the value of the graphed function when x = a.

Then we first need to identify x = a in the horizontal axis.
Then we move upwards (or downwards) until we meet the curve of the function.
Now you can move horizontally towards the vertical axis, where you can read the y-value associated to the x-value.

Now we can do these steps for each of the wanted values.

When x = -2, the value of the function is f(-2) = 1
When x = -0.5, the value of the function is f(-0.5) = 0.75
When x = 0, the value of the function is f(0) = 1.25
When x = 2.5, the value of the function is f(2.5) = 3
When x = 6, the value of the function is f(6) = 0

If you want to learn more about how to read graphs:

brainly.com/question/4025726

#SPJ1

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Ethan can blow 15 balloons in 20 minutes Junwei can blow 18 balloons in 25 minutes and vishal can blow 16 balloons in 21 minutes

monitta

Answer:

ethan blows fastest

Step-by-step explanation:

5 0

3 years ago

3. Here is a diagram of a softball field:

Crank

a. Length of the fence around the field = perimeter of quarter circle = 892.7 ft.

b. The area of the outfield is about 39,584 sq. ft..

<h3>What is the Perimeter of a Quarter Circle?</h3>

Perimeter of circle = 2πr

Perimeter of a quarter circle = 2r + 1/4(2πr).

a. The length of the fence around the field = perimeter of the quarter circle fence

= 2r + 1/4(2πr).

r = 250 ft

Plug in the value

The length of the fence around the field = 2(250) + 1/4(2 × π × 250)

= 892.7 ft.

b. Size of the outfield = area of the full field (quarter circle) - area of the infield (cicle)

= 1/4(πR²) - πr²

R = radius of the full field = 250 ft

r = radius of the infield = 110/2 = 55 ft

Plug in the values

Size of the outfield = 1/4(π × 250²) - π × 55²

= 49,087 - 9,503

= 39,584 sq. ft.

Learn more about perimeter of quarter circle on:

brainly.com/question/15976233

4 0

2 years ago

1. 8x – 4 = 12x + 12

olga_2 [115]

7(x-2) +3x=46
7x-14+3x=46
10x-14=46
10x=60
X=6

3 0

3 years ago

If the diameter of circle a measures half of the diameter of circle b, then the area of circle b is how many times the area of c

Eduardwww [97]

Circle b:

Diameter = x

Radius = $\frac{x}{2}$

Area = $\pi r^{2} = \pi ( \frac{x}{2} )^{2} = \frac{ \pi x^{2} }{4}$

Circle a:

Diameter = $\frac{x}{2}$

Radius = $\frac{x}{2} * \frac{1}{2} = \frac{x}{4}$

Area = $\pi r^{2} = \pi ( \frac{x}{4} )^{2} = \frac{ \pi x^{2} }{16}$

Thus,

Area of circle b to area of circle a

= $\frac{ \pi x^{2} }{4}$ ÷ $\frac{ \pi x^{2} }{16}$

= $\frac{ \pi x^{2} }{4}$ × $\frac{ 16 }{\pi x^{2}}$

= 4

Hence, the area of circle b is 4 times the area of circle a.

5 0

3 years ago

Can someone help with this math problem

katrin [286]

Answer:

20 ft long; 12 ft wide

Step-by-step explanation:

Let w = the width of the garden

Then l = w + 8

A = lw

A = (w + 8)w

=====

The sidewalk is 4 ft wide, so, for the big rectangle consisting of garden plus sidewalk:

Width = w +8

Length = w + 16

Area = (w + 8)(w + 16)

=====

The <em>difference</em> between the two areas is the area of the sidewalk (320 ft²).

(w + 8)(w + 16) - (w + 8)w = 320 Factor out w + 8

(w+ 8)(w + 16 – w) = 320 Combine like terms

(w+ 8) × 16 = 320 Divide each side by 16

w + 8 = 20 Subtract 8 from each side

w = 12 ft

l = 12 + 8

l = 20 ft

The garden is 20 ft long by 12 ft wide.

4 0

2 years ago