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2 years ago

Acetone (nail polish remover) has a density of 0.7857 g >cm3.

1 answer:

7 0

If acetone has a density of 0.7857 $\frac{g}{cm^{3} }$ the mass in grams of point A is 22.4 g and the volume at point B is 8.32 mL.

<h3>What is acetone?</h3>

Acetone is known as a chemical substance that is usually found in the environment but can also be produced artificially. Acetone is a polar organic product that interacts very well with water molecules, generating dipole-dipole relationships.It is colorless with a distinctive smell and taste, we find it in products known as <u>cleaning and personal care products</u>, but we can also use it as a solvent for substances.

Also in the environment in <u>plants, trees and in volcano emissions or in forest fires</u>, it does not become <em>toxic</em> in low doses but if it is exposed to an individual in high doses it can become <em>fatal</em>.

In the statement we can find that acetone has a density of 0.7857 $\frac{g}{cm^{3} }$ .

Therefore, we can confirm that if acetone has a density of 0.7857 $\frac{g}{cm^{3} }$ the mass in grams of point A is 22.4 g and the volume at point B is 8.32 mL.

To learn more about acetone visit: brainly.com/question/13334667?referrer=searchResults

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Rank the following groups in order of decreasing priority: A. bondCtbondCH B. bondCH(CH3)2 C. bondCH2CH3 D. bondCHdbondCH2

Lelu [443]

Answer:

(CH2)3CH3 > CH2CH2CH3 > CH2CH3 > CH3

Explanation:

Giving the following ; CH3, CH2CH3, CH2CH2CH3, (CH2)3CH3

Priority increases as the number of CH2 group increases and vice versa, as such the one with more CH2 group will be the highest priority and the least compound with the small CH2 group attached, will have the smallest priority.

The arrangement is as follows ; (CH2)3CH3 > CH2CH2CH3 > CH2CH3 > CH3

7 0

3 years ago

Which reaction will occur? 2NaBr I2 Right arrow. 2NaI Br2 2Fe Al2O3 Right arrow. 2Al Fe2O3 2AgNO3 Ni Right arrow. Ni(NO3)2 2Ag P

Likurg_2 [28]

The reaction that has been occurred will be $\rm 2\;Fe\;+\;Al_2O_3\;\rightarrow\;2\;Al\;+\;Fe_2O_3$ .

The chemical reaction has been defined as the interaction of the reactant molecules for the formation of the product. The changes have been taken place in the reactivity series and under specific conditions.

<h3>Reaction occur</h3>

The displacement reaction has been taken place based on the reactivity series. The more reactive element has been able to displace the less reactive element in the compound and form a new compound.

The following reactions have been analyzed as:

$\rm 2\;NaBr\;+\;I_2\;\rightarrow\;2\;NaI\;+\;Br_2$

In the reaction, Br has been replaced by Iodine. The iodine has been less reactive than Br and thus will not form the compound.

Thus, this reaction will not occur.

$\rm 2\;Fe\;+\;Al_2O_3\;\rightarrow\;2\;Al\;+\;Fe_2O_3$

In the reaction, Al has been replaced by Fe. The Fe is more reactive than Al. thus this reaction will occur.

$\rm 2\;AgNO_3\;+\;Ni\;\rightarrow\;Ni(NO_3)_2\;+\;2\;Ag$

The nickel has been less reactive than Ag, and thus will not be able to form the product.

Thus, this reaction will not occur.

$\rm Pb\;+\;Zn(C_2H_3O_2)_2\;\rightarrow\;Zn\;+\;Pb(C_2H_3O_2)_2$

The lead has been less reactive than Zn, and thus will not be able to form the product.

Thus, this reaction will not occur.

The reaction that has been occurred will be $\rm 2\;Fe\;+\;Al_2O_3\;\rightarrow\;2\;Al\;+\;Fe_2O_3$ .

Learn more about reactivity series, here:

brainly.com/question/10443908

8 0

2 years ago

The half-life of radium-226 is 1590 years. if a sample contains 100 mg, how many mg will remain after 1000 years?

AlladinOne [14]

Answer:

64.52 mg.

Explanation:

The following data were obtained from the question:

Half life (t½) = 1590 years

Initial amount (N₀) = 100 mg

Time (t) = 1000 years.

Final amount (N) =.?

Next, we shall determine the rate constant (K).

This is illustrated below:

Half life (t½) = 1590 years

Rate/decay constant (K) =?

K = 0.693 / t½

K = 0.693/1590

K = 4.36×10¯⁴ / year.

Finally, we shall determine the amount that will remain after 1000 years as follow:

Half life (t½) = 1590 years

Initial amount (N₀) = 100 mg

Time (t) = 1000 years.

Rate constant = 4.36×10¯⁴ / year.

Final amount (N) =.?

Log (N₀/N) = kt/2.3

Log (100/N) = 4.36×10¯⁴ × 1000/2.3

Log (100/N) = 0.436/2.3

Log (100/N) = 0.1896

Take the antilog

100/N = antilog (0.1896)

100/N = 1.55

Cross multiply

N x 1.55 = 100

Divide both side by 1.55

N = 100/1.55

N = 64.52 mg

Therefore, the amount that remained after 1000 years is 64.52 mg

7 0

3 years ago

Definition of periodic trends

Dmitriy789 [7]

Answer:

.Periodic trends are specific patterns in the properties of chemical elements that are revealed in the periodic table of elements. Major periodic trends include electronegativity, ionization energy, electron affinity, atomic radii, ionic radius, metallic character, and chemical reactivity.

7 0

3 years ago

]If a sample of pure iodine contains 4.69 x 1022 atoms of iodine, how many moles of iodine are in the sample? A=0.08 B=0.13 C=7.

Lorico [155]

It is B, and also for a moment I didn't understand that 4.69 x 10^22. I almost did this whole problem wrong.

6 0

3 years ago

Read 2 more answers