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3 years ago

Which statement is false?

Chemistry

1 answer:

baherus [9]3 years ago

6 0

Answer:

"The PDH complex is considered to be a reaction of the citric acid cycle" is the false statement

Explanation:

The PDH complex is involved in the oxidation of piruvate, producing acetate and free CO2 (besides ATP and NADH). Concomitantly, in presence of coenzyme A, it binds the acetate molecule to form Acetyl-CoA.

Acetyl-CoA, later, will enter the Krebs cycle reacting with oxalacetate to form citric acid.

The other statements options are true

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30cm^3 of a dilute solution of Ca(OH)2 required 11 cm^3 of 0.06 mol/dm^. Hcl for complete neutralization. Calculate the concentr

Alenkasestr [34]

Answer: Thus concentration of $Ca(OH)_2$ in $mol/dm^3$ is 0.011 and in $g/dm^3$ is 0.814

Explanation:

To calculate the concentration of $Ca(OH)_2$ , we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is $HCl$

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is $Ca(OH)_2$

We are given:

$n_1=1\\M_1=0.06mol/dm^3\\V_1=11cm^3=0.011dm^3\\n_2=2\\M_2=?\\V_2=30cm^3=0.030dm^3$ $1cm^3=0.001dm^3$

Putting values in above equation, we get:

$1\times 0.06mol/dm^3\times 0.011dm^3=2\times M_2\times 0.030dm^3\\\\M_2=0.011mol/dm^3$

The concentration in $g/dm^3$ is $0.011mol/dm^3\times 74g/mol=0.814g/dm^3$

Thus concentration of $Ca(OH)_2$ is $0.011mol/dm^3$ and $0.814g/dm^3$

4 0

3 years ago

Find the percentage composition of a compound that contains 1.94 g of carbon, 0.48 g of hydrogen, and 2.58 g of sulfur.

Svetradugi [14.3K]

Answer : The percentage composition of carbon, hydrogen and sulfur in a compound is, 38.8 %, 9.6 % and 51.6 % respectively.

Explanation :

To calculate the percentage composition of element in sample, we use the equation:

$\%\text{ composition of element}=\frac{\text{Mass of element}}{\text{Mass of sample}}\times 100$

Given:

Mass of carbon = 1.94 g

Mass of hydrogen = 0.48 g

Mass of sulfur = 2.58 g

First we have to calculate the mass of sample.

Mass of sample = Mass of carbon + Mass of hydrogen + Mass of sulfur

Mass of sample = 1.94 + 0.48 + 2.58 = 5.0 g

Now we have to calculate the percentage composition of a compound.

$\%\text{ composition of carbon}=\frac{1.94g}{5.0g}\times 100=38.8\%$

$\%\text{ composition of hydrogen}=\frac{0.48g}{5.0g}\times 100=9.6\%$

$\%\text{ composition of sulfur}=\frac{2.58g}{5.0g}\times 100=51.6\%$

Hence, the percentage composition of carbon, hydrogen and sulfur in a compound is, 38.8 %, 9.6 % and 51.6 % respectively.

3 0

3 years ago

As the moon orbits the ______________, its gravitational pull is______________ on the side of the earth closest to the _________

Fynjy0 [20]

Answer:

Earth

Strongest

Moon

Gravitational

Tide

Pulls

Bulge

Waves

Proximity

Low Tide

5 0

3 years ago

What effect does rapid exhalation of CO2 during exercise have on the concentration of H2CO3 in the blood?

BARSIC [14]

If there is a constant loss of $CO_{2}~(carbon~dioxide)$ the concentration of $H_{2} CO_{3}~(carbonic~acid)$ will be affected and decrease since $CO_{2}$ is a main component of $H_{2}CO_{3}$ .

Hope it helped,

BioTeacher101

3 0

3 years ago

Read 2 more answers

Differentiate between elements and mixtures

Ksenya-84 [330]

Answer:

ELEMENTS MIXTURE

Elements are made up of one kind of atoms. Mixtures are made up of two or more kinds of Compounds .

Elements cannot be broken down into simpler substances by any physical or chemical method. The various constituents are seperated by simple physical means

3 0

2 years ago

Read 2 more answers