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Norma-Jean [14]
3 years ago
6

Ok so I don't understand how to do this-

Chemistry
1 answer:
aleksandr82 [10.1K]3 years ago
3 0

Answer:

Oh, you are supposed to look up the yearly temp, and yearly rain for a certain area. I did this before!

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Where are the volcano located
Elza [17]

Answer:

In the ring of fire

Hope this acc helps

3 0
3 years ago
Which of the following represents a compound?<br><br> Na<br> CO2<br> Со<br> Mn
eduard

Answer:

CO2

Explanation:

Carbon dioxide is a chemical compound that consists of two oxygen atoms and one carbon atom

5 0
3 years ago
Josie created a Venn Diagram to determine the differences and similarities between weather and climate. PLSSS HELP I HAVE 15 MIN
DENIUS [597]

Answer:

Climate is long time intervals and weather is short time intervals

Explanation:

4 0
3 years ago
Predict which member of each pair will be more acidic. Explain your answers. (a) methanol or tert-butyl alcohol (b) 2-chloroprop
Art [367]

Answer:

A. Methanol

B. 2-chloropropan-1-ol

C. 2,2-dichloroethanol

D. 2,2-difluoropropan-1-ol

Explanation:

Primary alcohols are stronger acids than secondary alcohols which are stronger than tertiary alcohols.

This trend is so because of the stability of the alkoxide ion formed(stabilising the base, increases the acidity). A more stabilised alkoxide ion is a weaker conjugate base (dissociation of an acid in water).

By electronic factors, When there are alkyl groups donating electrons, the density of electrons on th O- will increase a d thereby make it less stable.

By stearic factors, More alkyl group bonded to the -OH would mean the bulkier the alkoxide ion which would be harder to stabilise.

Down the group of the periodic table, basicity (metallic character) decreases as we go from F– to Cl– to Br– to I– because that negative charge is being spread out over a larger volume that is electronegativity decreases down the group.

Electronegative atoms give rise to inductive effect and a decrease in indutive effects leads to a decrease in acidity. Therefore an Increasing distance from the -OH group lsads to a decrease in acidity.

From above,

A. Methanol

B. 2-chloropropan-1-ol

C. 2,2-dichloroethanol

D. 2,2-difluoropropan-1-ol

6 0
4 years ago
How many grams of potassium iodine, kl,must be added to 500.0 grams of water to produce a 6.00% solution ?
GuDViN [60]

Answer:

grams KI needed = 31.9 grams

Explanation:

? g KI + 500 g water => 6.0% KI solution

let x = grams KI needed.

Percent = part/total x 100% = (x/x+500)·100% = 6.0%

Solve for 'x' ...

x / x + 500 = 6/100 = 0.06 => x = 0.06(x + 500) => x = 0.06x + 30

x - 0.06x = 30 => 0.94x = 30 => x = 30/0.94 = 31.9 gms KI needed.  

6 0
3 years ago
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