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2 years ago

The first wave that forms when the wind begins to blow across the ocean surface is a ________.

Physics

1 answer:

seraphim [82]2 years ago

8 0

The first wave that forms when the wind begins to blow across the ocean surface is a <u>capillary wave</u>

The capillary waves represent the initial state of a wave that are produced by vortices in a flat sea. When the winds blow over an ocean, energy is transferred from the wind to the sea. and that produced the waves. They are also presented as ripples.

The capillary waves have a wavelength less than 1.7 cm or 0.68 inches and its speed of 0.2 to 0.3 meter per second.

<h3>What is a capillary wave?</h3>

It is a wave that is travelling along the interface boundary of a fluid and it is influenced by the effect of surface tension and the gravity.

Learn more about capillary wave at brainly.com/question/15663649

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While traveling along a highway a driver slows from 34 m/s to 17 m/s in 6 seconds. What is the automobiles acceleration?

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Answer:

-2.83 m/s²

Explanation:

Initial velocity (u) = 34 m/s
Final velocity (v) = 17 m/s
Time taken (t) = 6 seconds

❖ Acceleration is defined as the rate of change in velocity with time.

→ a = (v - u)/t

v denotes final velocity
a denotes acceleration
u denotes initial velocity
t denotes time

→ a = (17 - 34)/6 m/s²

→ a = -17/6 m/s²

<h3>→ Acceleration = -2.83 m/s²</h3>

(Minus sign implies that the velocity is decreasing.)

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Consider a book that weighs 15 N at rest on a flat table. How many newtons of support does the table provide?

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8. A turtle crawls along a straight line, which we will call the x-axis with the positive direction to the right. The equation f

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(a) The turtle's initial velocity is 4 m/s, initial position of the turtle is 5 cm, and initial acceleration is -1.25 m/s².

(b) The time when the velocity of the turtle is zero is 3.2 s.

(d) The time taken for the turtle to travel 30 cm is 0.08 s.

<h3>Initial velocity of the turtle</h3>

The initial velocity of the turtle is calculated as follows;

$v = \frac{dx}{dt} \\\\x = 5 + 4t -0.625t^2\\\\v(t) = 4 - 1.25t\\\\v(0) = 4-0\\\\v(0) = 4 \ m/s$

<h3>Initial acceleration of the turtle</h3>

The initial acceleration of the turtle is calculated as follows;

$a = \frac{dv}{dt} \\\\v(t) = 4 - 1.25t\\\\a = -1.25\ m/s^2$

<h3>Initial position of the turtle</h3>

x(t) = 5 + 4t - 0.625t²

x(0) = 5 cm

<h3>Time when the velocity becomes zero</h3>

v(t) = 4 - 1.25t

0 = 4 - 1.25t

1.25t = 4

t = 4/1.25

t = 3.2 s

<h3>Time taken to return to starting point</h3>

The total distance traveled is calculated as follows

v² = u² + 2ad

0 = (4)² + 2(-1.25)d

0 = 16 - 2.5d

2.5d = 16

d = 16/2.5

d = 6.4 m

Time to travel the given distance;

d = ut + ¹/₂at²

6.4 = (4)t + ¹/₂(-1.25)t²

6.4 = 4t - 0.625t²

0.625t² - 4t + 6.4 = 0

solve the quadratic equation using formula method;

t = 3.2 s

The time travel the distance two times, = 2 x 3.2 s = 6.4 s

<h3>Time taken for the turtle to travel 30 cm</h3>

d = ut + ¹/₂at²

0.3 = (4)t + ¹/₂(-1.25)t²

0.3 = 4t - 0.625t²

0.625t² - 4t + 0.3 = 0

solve the quadratic equation using formula method;

t = 0.08 s

Learn more about velocity here: brainly.com/question/6504879

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