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2 years ago

The first wave that forms when the wind begins to blow across the ocean surface is a ________.

Physics

1 answer:

seraphim [82]2 years ago

8 0

The first wave that forms when the wind begins to blow across the ocean surface is a <u>capillary wave</u>

The capillary waves represent the initial state of a wave that are produced by vortices in a flat sea. When the winds blow over an ocean, energy is transferred from the wind to the sea. and that produced the waves. They are also presented as ripples.

The capillary waves have a wavelength less than 1.7 cm or 0.68 inches and its speed of 0.2 to 0.3 meter per second.

<h3>What is a capillary wave?</h3>

It is a wave that is travelling along the interface boundary of a fluid and it is influenced by the effect of surface tension and the gravity.

Learn more about capillary wave at brainly.com/question/15663649

#SPJ4

You might be interested in

In Hooke’s law, what does the x represent?

Mice21 [21]

Answer: C

X = Displacement of the spring

Hooke's law: It states that the applied force F is proportional to the displacement of spring .

F ∝ x

Where, x = displacement of spring in meters

F = force, measured in Newtons

In another words The force F is equal to the constant K times the disparagement.

F = k.x

Where k is constant and it depends on elastic material.

Spring has restorative force.

If the spring moves in opposite direction then,

F = - k.x

A negative sign indicates that the spring resists and force is to the left. The compression of the spring is greater than the restoring force.

Example: A mass 'm' stretches a spring at a displacement x.

6 0

3 years ago

Using an example, explain how small atoms are.

Aliun [14]

Unlike a ball, an atom doesn't have a fixed radius. The radius of an atom can only be found by measuring the distance between the nuclei of two touching atoms, and then halving that distance... Does that answer your question?

4 0

3 years ago

The diameter of Earth (to two significant figures) is 7900 miles. Calculate its circumference.

Bess [88]

Answer:

The circumference of the Earth is 24818.58 miles

Explanation:

Analysis conceptual : The formula of the circumference is the following:

L= π*D Formula (1)

Where:

L : is the length of the circumference in miles (mi)

π : is the constant

D : is the diameter of the circumference in miles (mi)

Known data

π = 3.1416

D= 7900 miles: Diameter of the Earth

Problem development

We apply the formula 1 to calculate the circumference of the Earth (L):

L= π*7900 miles

L= 24818.58 miles

8 0

3 years ago

The total electric flux from a cubical box 26.0 cm on a side is 1840 N m2/C. What charge is enclosed by the box?

vitfil [10]

The expression of the electric flux is

$\Phi = \frac{Q}{\epsilon_0}$

Here,

Q = Total charge enclosed in the closed surface

$\epsilon_0$ = Permittivity due to free space

Rearranging to find the charge,

$Q = \epsilon_0 \Phi$

Replacing with our values we have finally

$Q = (8.85*10^{-12}F\cdot m^{-1})(1.84*10^3 N\cdot m^2/C)$

$Q = 1.6284*10^{-8} C$ $(\frac{10^9nC}{1C})$

$Q = 0.1684nC$

The charge enclosed by the box is 0.1684nC

The sign of the charge can be decided by using the direction of the flux. The charge enclosed by the cube can be calculated by using the electric flux and the permitivity of free space.

7 0

3 years ago

The diameter of a copper atom is approximately 2.28e-10 m. The massof one mole of copper is 64 grams. Assume that the atoms area

KIM [24]

1) Mass of one copper atom: $1.063\cdot 10^{-22} kg$

2) There are $9.33\cdot 10^{24}$ atoms in the cube

3) Mass of the cubical block: 992 kg

Explanation:

We are told here that the mass of one mole of copper is

$M=64 g$

for

$n=1 mol$ (number of moles)

We also know that the number of atoms inside 1 mole of substance is equal to Avogadro number:

$N_A = 6.022\cdot 10^{23}$

This means that $N_A$ atoms of copper have a mass of M = 64 g. Therefore, we can find the mass of one copper atom by dividing the total mass by the avogadro number:

$m=\frac{M}{N_A}=\frac{64}{6.022\cdot 10^{23}}=1.063\cdot 10^{-22} kg$

We are told that the diameter of a copper atom is

$d=2.28\cdot 10^{-10} m$

We can assume that the atoms are arranged in a cube, and that they are all attached to each other; so the side of the cube can be written as size of one atom multiplied by the number of atom per side:

$L=Nd$