The first wave that forms when the wind begins to blow across the ocean surface is a ________.

Physics

1 answer:

seraphim [82]2 years ago

8 0

The first wave that forms when the wind begins to blow across the ocean surface is a <u>capillary wave</u>

The capillary waves represent the initial state of a wave that are produced by vortices in a flat sea. When the winds blow over an ocean, energy is transferred from the wind to the sea. and that produced the waves. They are also presented as ripples.

The capillary waves have a wavelength less than 1.7 cm or 0.68 inches and its speed of 0.2 to 0.3 meter per second.

<h3>What is a capillary wave?</h3>

It is a wave that is travelling along the interface boundary of a fluid and it is influenced by the effect of surface tension and the gravity.

Learn more about capillary wave at brainly.com/question/15663649

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Are wind-driven currents found near the surface of the oceans or in the deep waters of the ocean?

drek231 [11]

Wind-driven currents are found NEAR THE SURFACE of the oceans

Explanation:

Surface currents are at the interphase between the hydrosphere and atmosphere. Therefore the feel the greatest effect of drag by wind currents, especially prevailing winds (that blow predominantly in one direction like westerlies and easterlies) within the lower atmosphere. The deep currents, on the other hand, are more influenced by Coriolis effect of the earth’s rotation. It is these differences in influences of surface and deeper currents that cause Ekman transport in oceans.

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5 0

4 years ago

Which of the following statements describe the transfer of energy a. Collision of atoms causing nuclear reactions B. A car speed

oksano4ka [1.4K]

I think the answer would be A.

8 0

3 years ago

A concave mirror produces a real image that is three times as large as the object. If the object is 20 cm in front of the mirror

TiliK225 [7]

Answer:

The image is produced 60 cm behind the mirror

The focal length of the mirror is 30 cm

Explanation:

u = Object distance = 20 cm

v = Image distance

f = Focal length

m = Magnification = 3

$m=-\frac{v}{u}\\\Rightarrow 3=-\frac{v}{20}\\\Rightarrow v=-3\times 20\\\Rightarrow v=-60\ cm$

The image is produced 60 cm behind the mirror

$\frac{1}{f}=\frac{1}{u}+\frac{1}{v}\\\Rightarrow \frac{1}{f}=\frac{1}{20}+\frac{1}{-60}\\\Rightarrow \frac{1}{f}=\frac{1}{30}\\\Rightarrow f=\frac{30}{1}=30\ cm$