Consider a book that weighs 15 N at rest on a flat table. How many newtons of support does the table provide?

If the primary coil of a transformer has 200 turns and is supplied with 120 v ac power, how many turns must the secondary coil h

Oduvanchick [21]

The ratio of the turns to the voltage should be equal
i.e: 200/120 = t/12
so the secondary coil should have 20 turns

5 0

3 years ago

Find the radius of the circle formed by the intersection of a sphere of diameter 26 units and a plane that is 5 units away from

horrorfan [7]

Answer:

12 units

Explanation:

This problem can be solved if we take into account the equation for a sphere

$x^{2}+y^{2}+z^{2}=r^{2}\\x^{2}+y^{2}+z^{2}=(\frac{26}{2})^{2}=13^{2}$

where we took that the radius is 13 units. If we take z=5 and we replace this value in the equation of the sphere we have

$x^{2}+y^{2}+(5)^{5}=13^{2}\\x^{2}+y^{2}=144=(12)^{2}$

where we have taken x2 +y2 because if the equation of a circunference.

In this case the intersection is made when we take z=5, for this value the sphere and the plane coincides in values.

Hence, the radius is 12 units

I hope this is useful for you

regards

8 0

3 years ago

A block with a mass M = 4.85 kg is resting on a slide that has a curved surface. There is no friction. The speed of the block af

natali 33 [55]

Answer:

The correct option is a

Explanation:

From the question we are told that

The mass of the block is $m = 4.84 \ kg$

The height of the vertical drop is $h = 19.6 \ m$

Generally from the law of energy conservation , the potential energy at the top of the slide is equal to the kinetic energy at the point after sliding this can be mathematically represented as

$PE = KE$

i.e $m * g * h = \frac{1}{2} * m * v^2$

=> $gh = 0.5 v^2$

=> $v = \sqrt{\frac{9.8 * 19.6}{0.5 } }$

=> $v = 19.6 \ m/s$

4 0

2 years ago

Red light of wavelength 633 nm from a helium-neon laser passes through a slit 0.400mm wide. The diffraction pattern is observed

kogti [31]

Answer:

a) $y_{first}=5.3mm$

b) $y_{second}=10.6-5.3 =5.3 mm$

Explanation:

a)

The width of the central bright in this diffraction pattern is given by:

$y=\frac{m\lambda D}{a}$ when m is a natural number.

here:

m is 1 (to find the central bright fringe)
D is the distance from the slit to the screen
a is the slit wide
λ is the wavelength

So we have:

$y_{first}=\frac{633*10^{9}*3.35}{0.0004}$

$y_{first}=5.3mm$

b)

Now, if we do m=2 we can find the distance to the second minima.

$y_{2}=\frac{2*633*10^{9}*3.35}{0.0004}$

$y_{2}=10.6 mm$

Now we need to subtract these distance, to get the width of the first bright fringe :

$y_{second}=10.6-5.3 =5.3 mm$

I hope it heps you!

4 0

2 years ago

The velocity time graph of an object is shown below. How far does the object travel in the time interval t =4 s to t = 6 s?

Trava [24]

The distance covered by the object between t =4 s and t = 6 s is 4 m

Explanation:

In a velocity-time graph, the distance covered by the object represented can be found by calculating the area under the curve.

Therefore, the distance covered by the object between t = 4 s and t = 6 s is the area under the curve between 4 s and 6 s.

We see that we have to calculate the area of a triangle, with:

Base:

$b=6-4 = 2$

And height:

$h=4-0 = 4$

Therefore, the area is

$A=\frac{1}{2}bh=\frac{1}{2}(2)(4)=4$

So, the distance covered by the object is 4 m.

Learn more about distance:

brainly.com/question/3969582

#LearnwithBrainly

3 0

3 years ago