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hoa [83]
3 years ago
10

is there difference if you pull a block down a hill or if you push a block down a hill. Or if you push a block up a hill or pull

it up ? For example if you PULL a block down a hill it would be F+Fg||-fk =ma (the force you are using +Fsinθ - kinetic friction =ma. Would this change if you PUSH the block down? ​
Physics
1 answer:
Afina-wow [57]3 years ago
8 0

Answer:

Yes it will be changed

Explanation:

Lifting up requires potential energy while dropping down requires kinetic, both will have different equations

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A parallel-plate capacitor has a plate separation of 1.5 mm and is charged to 450 V. 1) If an electron leaves the negative plate
Bumek [7]

Answer:

Explanation:

this is the answer to your question

8 0
3 years ago
A body moving at .500c with respect to an observer
lakkis [162]

Answer:

0.8c and -0.14c

Explanation:

The first fragment will have a speed of +0.5c respect of a frame of reference moving at +0.5c

Lest name v the velocity of the frame of reference, and u' the velocity of the object respect of this moving frame of reference.

The Lorentz transform for velocity is:

u = (u' + v) / (1 + (u' * v) / c^2)

u = (0.5c + 0.5c) / (1 + (0.5c * 0.5c) / c^2) = 0.8c

The other fragment has a velocity of u' = -0.6c respect of the moving frame of reference.

u = (-0.6v + 0.5c) / (1 + (0.5c * 0.5c) / c^2) = -0.14c

6 0
3 years ago
Two rams run toward each other. One ram has a mass of 49 kg and runs west
olga nikolaevna [1]

Answer: (d)

Explanation:

Given

Mass of the first ram m_1=49\ kg

The velocity of this ram is v_1=-7\ m/s

Mass of the second ram m_2=52\ kg

The velocity of this ram v_2=9\ m/s

They combined after the collision

Conserving the momentum

\Rightarrow m_1v_1+m_2v_2=(m_1+m_2)v\\\Rightarrow 49\times (-7)+52\times (9)=(52+49)v\\\Rightarrow v=\dfrac{125}{101}\ m/s \quad[\text{east}]

Momentum after the collision will be

\Rightarrow 101\times \dfrac{125}{101}=125\ kg-m/s\ \text{East}

Therefore, option (d) is correct

4 0
3 years ago
An average force of 328 N acts for a time interval of 0.05s on a golf ball
blagie [28]
Depends on how strong you are. People can hit it anywhere between a few inches and 500 yards.
4 0
3 years ago
A 25 newton force applied on an object moves it 50 meters. The angle between the force and displacement is 40.0 degrees. What is
zvonat [6]
Work done is when a force is exerted to cause a displacement in a certain object. 
the equation for work done ;
work done = force applied * displacement of the object 
when the force applied is not in the same direction as that of the displacement of the object then the effect of the force is not its whole value. The force is then applied at an angle to that of the displacement of the object, then the resultant force is the force exerted* cos of the angle between force and displacement, in this instance the angle is 40 °.
the new equation is then;
work done = force cos 40° * displacement
after substitution,
work = 25 N * 0.76 * 50 m
         = 957.55 J
round it off
         = 9.6 *10² J
the correct answer is B
5 0
3 years ago
Read 2 more answers
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