The centripetal acceleration of an object is given by the relation,
![Ac =V^2/R](https://tex.z-dn.net/?f=Ac%20%3DV%5E2%2FR)
where Ac = centripetal acceleration =
R = radius of rotation = 15 m
V = speed of astronaut
Hence, ![\frac{V^2}{15} =98](https://tex.z-dn.net/?f=%5Cfrac%7BV%5E2%7D%7B15%7D%20%3D98)
solving this we get, V = 38.34 m/s
Answer:
The answer is C. Seismic waves.
Explanation:
- <u>Seismic waves are waves of energy that travel through Earth's layers, and are a result of earthquakes.</u>
Answer:
Explanation:
a ) Let let the frictional force needed be F
Work done by frictional force = kinetic energy of car
F x 107 = 1/2 x 1400 x 35²
F = 8014 N
b )
maximum possible static friction
= μ mg
where μ is coefficient of static friction
= .5 x 1400 x 9.8
= 6860 N
c )
work done by friction for μ = .4
= .4 x 1400 x 9.8 x 107
= 587216 J
Initial Kinetic energy
= .5 x 1400 x 35 x 35
= 857500 J
Kinetic energy at the at of collision
= 857500 - 587216
= 270284 J
So , if v be the velocity at the time of collision
1/2 mv² = 270284
v = 19.65 m /s
d ) centripetal force required
= mv₀² / d which will be provided by frictional force
= (1400 x 35 x 35) / 107
= 16028 N
Maximum frictional force possible
= μmg
= .5 x 1400 x 9.8
= 6860 N
So this is not possible.
Answer:
ΔK = 24 joules.
Explanation:
Δ
Work done on the object
Work is equal to the dot product of force supplied and the displacement of the object.
* Δ![s](https://tex.z-dn.net/?f=s)
Δ
can be found by subtracting the vectors (7.0, -8.0) and (11.0, -5.0), which is written as Δ
= (11.0 - 7.0, -5.0 - -8.0) which equals (4.0, 3.0).
This gives us
*
=
=
J