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aleksklad [387]
1 year ago
11

​For the following 3 experimental set-ups identify:

Chemistry
1 answer:
adell [148]1 year ago
5 0

The independent variable is the type of liquid and the dependent variable growth of the plants.

<h3>What is an experiment?</h3>

An experiment is used to establish the relationship between causes and effect in each of the following cases, let us determine the dependent and independent variable.

1) The independent variable is the type of liquid and the dependent variable growth of the plants. The constants are the plants and the land. A valid hypothesis is; "The growth of the plants depends on the type of liquid used to water the plants"

2) The independent variable is the mode of transport and the dependent variable is the time taken to reach the market. The constant is the distance covered. A valid hypothesis is; "The time taken to arrive at the grocery store depends on the mode of transport used"

3) The independent variable is the kind of app and the dependent variable is the  battery life. The constant is the phone used while the hypothesis is; "Certain apps delete the battery faster than others"

Learn  more about experiment:brainly.com/question/11256472

#SPJ1

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Answer:

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Explanation:

Physical properties are something that is reverseable or has no change visible. Chemical properties are something that is NOT reverseable.

Chemical: Gas forming or Color Changing. (ETC.)

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2 years ago
A solution of pH 5 is diluted 100 times. Find the pH of the resulting solution.
liq [111]
First, we calculate of the concentration of the H+ ions in the solution from the pH given. Then, calculate the new concentration after dilution. Calculation are as follows:

pH = -log[H+]
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M1V1 = M2V2
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pH =  -log[<span>1 x 10^-7</span>]
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3 0
3 years ago
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100.mL of a .795 M solution of KBr is diluted to 500.mL. what is the new concentration of the solution?
kap26 [50]

Answer:

0.159 M

Explanation:

convert from mL to L then use the equation:

M1V1 = M2V2

rearrange to find M2

\frac{M1V1}{V2} = M2

\frac{(0.795 M)(0.100 L)}{0.500 L} = 0.159 M

4 0
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