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Sphinxa [80]
3 years ago
13

What volume would 2.25 moles of Ne gas occupy at STP?

Chemistry
1 answer:
Dafna1 [17]3 years ago
8 0
As we know that one mole of any Ideal gas at standard temperature and pressure occupies exactly 22.4 dm³ volume.

Solution for problem:

When 1 mole Neon (Ne) occupies 22.4 dm³ at STP then the volume occupied by 2.25 moles of Neon is calculated as,

                                             = ( 22.4 dm³ × 2.25 moles ) ÷ 1 mole
                
                                             = 50.4 dm³                   1dm³ = 1 L

Result:

So
, 50.4 dm³ (Liter) volume will be occupied by 2.25 moles of Neon gas if it acts ideally at STP.
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How much heat is released when 24.8 g of ch4 is burned in excess oxygen gas?
balu736 [363]

The given question is incomplete. The complete question is:

How much heat is produced when 24.8 g of CH_4 is burned in excess oxygen gas

Given: CH _4
+2O_2\rightarrow CO_2+2H_2O  ΔH= −802 kJ.

Answer: 1243.1 kJ

Explanation:

Heat of combustion is the amount of heat released on complete combustion of 1 mole of substance.

Given :

Amount of heat released on combustion of  1 mole of methane = 802 kJ kJ/mol

According to avogadro's law, 1 mole of every substance occupies 22.4 L at NTP, weighs equal to the molecular mass and contains avogadro's number 6.023\times 10^{23} of particles.

1 mole of CH_4 weighs = 16 g  

Thus we can say:  

16 g of CH_4 on combustion releases heat = 802 kJ

Thus 24.8 g of CH_4 on combustion releases =\frac{802}{16}\times 24.8=1243.1kJ

Thus heat released when 24.8 g of methane is burned in excess oxygen gas is 1243.1 kJ

4 0
3 years ago
Tissues are made up of two or more different types of organs
Gala2k [10]

Answer:

false

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4 0
3 years ago
If you are calculating the grams to mL ratio, you are trying to find the object’s…
Alex

Answer:

Density

Explanation:

The ratio of mass to the volume of an object is called its density. Unit of mass is grams and that of volume is mL.

Density = mass/volume

\text{Density}=\dfrac{\text{grams}}{\text{mL}}\\\\=\text{grams/mL}

If you are calculating the grams to mL ratio, it means that we are trying to find the object's density.

4 0
3 years ago
What volume of 0.160 m li2s solution is required to completely react with 130 ml of 0.160 m co no3 2?
Over [174]
The  volume  of  0.160    m   Li2S  solution  required  to  completely  react  with  130 ml  of 0.160  CO(NO3)2  is calculated   as  below

write the  reacting  equation

Co(NO3)2 +  Li2S = 2LiNO3  +  COS

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=  130 ml  x  0.160=20.8  moles

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volume  of Lis  is  therefore =  moles of Lis/ molarity  of LiS

=  20.8/0.160 =  130 Ml
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3 years ago
**PLATO QUESTION, PLEASE ANSWER CORRECTLY, THANKS SO MUCH**
OLga [1]
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Reason:
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3 years ago
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