Answer:
[KOH] = 0.10M in KOH
Explanation:
Molar Concentration [M] = moles solute/volume solution in liters
moles KOH = 0.56g/56g/mole = 0.01mole
Volume of solution = 100cm³ = 100ml = 0.10 liter
[KOH] = 0.01 mole KOH / 0.10 liter solution = 0.10M in KOH
Answer:
Yes Concurred,but where is the question
Answer:
A) increasing tension in the vibrating object.
VSEPR notation gives a general formula for classifying chemical species based on the number of electron pairs around a central atom. However, not all species have the same molecules.
For example, carbon dioxide and surfer dioxide are both species, but one is linear and another one is bent.
Answer:
The value of the equilibrium constant = 5.213
Explanation:
Here
(equilibrium constant) is referred to as the partial pressure of product divided by the partial pressure of reactant with each pressure term raised to power that is equal to its stoichiometric coefficient in balanced equation
.
As such only gas appear in
expression as solids takes a value of 1;
SO ; in the given equation from the question:
2 A (g) + B (s) ----> 2 C(s) + D (g)
![K_p = \dfrac{[D]}{[A]^2}](https://tex.z-dn.net/?f=K_p%20%3D%20%5Cdfrac%7B%5BD%5D%7D%7B%5BA%5D%5E2%7D)
![K_p = \dfrac{2.71}{0.721^2}](https://tex.z-dn.net/?f=K_p%20%3D%20%5Cdfrac%7B2.71%7D%7B0.721%5E2%7D)
![K_p = 5.213](https://tex.z-dn.net/?f=K_p%20%3D%205.213)
The value of the equilibrium constant = 5.213