2 years ago

Anthony wrote 52.066 as the standard form for fifty-two and sixty-six hundredths. Is he correct? Explain.

Mathematics

1 answer:

aleksley [76]2 years ago

7 0

Answer:

That's incorrect. He wrote the form for fifty-two and sixty-six thousandths. The correct number is 52.66.

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1) 2/7×1/2 2) 5/8×4/5 3) 1/6×2/3 4) 1/3×3/4 5) 1/2×2/3 6) 1/3×2/5

nignag [31]

1) 1/7
2) 1/2
3) 1/9
4) 1/4
5) 1/3
6) 2/15
hope this helped:)

5 0

3 years ago

Given f as described below.

Maru [420]

Answer:

f (0) = 0

Step-by-step explanation:

As Domain = {all whole numbers}

Range is R = {0, 1, 2, 3, 4, 5, 6, 7, 8, 9} 

then f (0) = 0 which is its largest place value digit.

3 0

3 years ago

Solve h = −16t2 + 36t + 4.

kvasek [131]

I can do each of the things I asked above.
So, let's change this into vertex form:
$h=-16t^2+36t+4$
$h=(-16t^2+36t)+4$
$h=-16(t^2-2.25t)+4$
$h=-16(t^2-2.25t+1.27-1.27)+4$
$h=-16(t^2-2.25t+1.27)+20.32+4$
$h=-16(t-1.125)^2+24.32$
The vertex is at (1.125,24.32)
Answers may vary due to rounding

Factored Form:
$h = -16t^2 + 36t + 4$
$h = -4\left(4t^2-9t-1\right)$

Quadratic Formula:
$x = \frac{-b +/- \sqrt{b^2-4(a)(c)}}{2a}$
h = -16t^2 + 36t + 4
a = -16 b = 36 c = 4
$h = \frac{-(36) +/- \sqrt{(36)^2-4(-16)(4)}}{2(-16)}$
$h = \frac{-36 +/- \sqrt{1552}}{-32}$
$h = ≈-0.11$
$h = ≈2.36$

5 0

3 years ago

Pls Help thanks :) ......

IgorC [24]

1. Given
2. Addition property
3. Division property

7 0

3 years ago

Multiply the following radicals (do NOT simplify) 2/4 x 416

Tpy6a [65]

Answer:

208

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Anthony wrote 52.066 as the standard form for fifty-two and sixty-six hundredths. Is he correct? Explain.​

Anthony wrote 52.066 as the standard form for fifty-two and sixty-six hundredths. Is he correct? Explain.