How many different ID cards can be made if there are six digits on a card and no digit can be used more than once?

valina [46]

Answer:

Step-by-step explanation:

You have 3 unknowns: a, b, and c. It's our job to find them algebraically. I'm going to start with the point where x = 0 and y = 7. You'll see why in a minute. Filling in the standard form of a quadratic

$y=ax^2+bx+c$ using (0, 7):

$7=a(0)^2+b(0)+c$ gives you that c = 7. We will use that value now when we write the next 2 equations. Now the point (-2, 19):

$19=a(-2)^2+b(-2)+7$ and

$19=4a-2b+7$ so

12 = 4a - 2b

Now for the next point (-1, 12):

$12=a(-1)^2+b(-1)+7$ and

$12=a-b+7$ so

5 = a - b

Now we have a system of equations (the 2 bold font equations) that we will solve by elimination:

12 = 4a - 2b

5 = a - b

Multiply the bottom equation by -4 to get a new system:

12 = 4a - 2b

-20 = -4a + 4b

Add those together to get rid of the a terms and end up with

-8 = 2b so

b = -4

Now we can sub in -4 for b to solve for a. I'm using the second bold type equation to do this:

5 = a - (-4) and

5 = a + 4 so

a = 1 and the equation for the quadratic function is

$y=x^2-4x+7$

7 0

3 years ago

A researcher obtains t = 2.35 for a repeated-measures study using a sample of n = 8 participants. Based on this t value, what is

ZanzabumX [31]

Answer:

$p_v =2*P(t_{7}>2.35)=2*0.0255=0.051$

If we compare the p value and using the significance level given $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% or 1% of significance we fail to reject the null hypothesis.

Step-by-step explanation:

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level is not provided but we can assume it as $\alpha=0.05$ . First we need to calculate the degrees of freedom like this:

$df=n-1=8-1=7$

The next step would be calculate the p value for this test. Since is a bilateral test or two tailed test, the p value would be:

$p_v =2*P(t_{7}>2.35)=2*0.0255=0.051$

If we compare the p value and using the significance level given $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% or 1% of significance we fail to reject the null hypothesis.

5 0

3 years ago

Someone please help me I’ll give out brainliest please dont answer if you don’t know

NARA [144]

Answer:

m=2

Step-by-step explanation:

42=8m+13m

or,42=21m

or,42/21=m

or,m=2

This is the required answer for m.

To check,

42=8×2+13×2

42=16+26

42=42

Correct

7 0

3 years ago

Rewrite the parametric equations by eliminating the parameter. Select ONE.

Vinil7 [7]

Answer:

$Y=(X-7)/2$

Step-by-step explanation:

we have

$X=2t+3$ -----> equation A

$Y=t-2$ -----> $t=Y+2$ -----> equation B

Substitute equation B in equation A

$X=2(Y+2)+3$

$X=2Y+4+3$

$X=2Y+7$

solve for Y

$2Y=X-7$

$Y=(X-7)/2$

6 0

2 years ago

Please give me the answer to number 5 and explain how to do it.

Goryan [66]

The equation is simply 8s where s is the length of a side. There are 8 sides. You are just adding the length of all 8 sides together to get the perimeter.

4 0

2 years ago