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igomit [66]
2 years ago
9

HIN

Mathematics
1 answer:
Elis [28]2 years ago
5 0

should just be 1/2

Sorry if im wrong

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A(-3, 9) and B(5, 9) are the endpoints of the diameter of a circle. Use these points to find the standard equation of the circle
aksik [14]
Check the picture below.

notice the midpoint of the diameter segment, is just 1,9.

also, recall the radius is half the diameter, notice how long the radius is, just 4 units.

\bf \textit{equation of a circle}\\\\ 
(x-{{ h}})^2+(y-{{ k}})^2={{ r}}^2
\qquad 
\begin{array}{lllll}
center\ (&{{ h}},&{{ k}})\qquad 
radius=&{{ r}}\\
&1&9&4
\end{array}

7 0
4 years ago
A race at travels at a rate of 205 mph how far would it travel in 3 hours?
Liono4ka [1.6K]
615 miles, because you do 205*3
8 0
3 years ago
Find the distance between the two points in simplest radical form.<br> (-2, 1) and (-8, 9)
Vika [28.1K]

Answer:

10

Step-by-step explanation:

d = √(x2 - x1)² + (y2 - y1)²

d = √(-8 - -2)² + (9 - 1)²  

d = √(-6)² + (8)²  

d = √(36) + (64)

d = √100

d = 10

3 0
3 years ago
The center of a circle is the point (3, 2). if the point (6, −2) lies on this circle, find the standard equation for the circle.
garri49 [273]
Given 
centre of circle O(3,2)=O(x0,y0)
point on circle P(6,-2)

Standard equation of circle:
(x-x0)^2+(y-y0)^2=r^2

r=radius of circle
= (distance OP)
= sqrt((6-3)^2+(-2-2)^2)
=sqrt(3^2+(-4)^2)
=sqrt(25)

=> 
r^2=(sqrt(25))^2=25

Equation of circle
(x-x0)^2+(y-y0)^2=r^2
(x-3)^2+(y-2)^2=25   ............... standard equation of circle
5 0
4 years ago
I built 27 with base ten blocks.then i built 20 and 30.i know 27 is closer to 30 than 20 because
maksim [4K]
Hey You!

You know 27 is closer to 30 because the number is above 25, and it would take 7 blocks to get closer to 20 and only 3 to 30.
8 0
4 years ago
Read 2 more answers
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