Answer:
is equal to the action force , but acts in the opposite direction.
Explanation:
- All you need to solve is apply Newton's third law.
It states that
- Every action has an equal and opposite reaction
Or
![\\ \tt\bull\rightarrowtail F_A=-F_A](https://tex.z-dn.net/?f=%5C%5C%20%5Ctt%5Cbull%5Crightarrowtail%20F_A%3D-F_A)
Answer:
The 35-watt light bulb does a work of 46200 joules in 1320 seconds.
Explanation:
From Physics we remember the definition of work (
), measured in joules, by the following integral equation:
(1)
Where
is the power, measured in watts.
If the power is stable in time, then the work can be calculated by the following algebraic equation:
(2)
If we know that
and
, then the work done by the 35-light bulb is:
![W = (35\,W)\cdot (1320\,s)](https://tex.z-dn.net/?f=W%20%3D%20%2835%5C%2CW%29%5Ccdot%20%281320%5C%2Cs%29)
![W = 46200\,J](https://tex.z-dn.net/?f=W%20%3D%2046200%5C%2CJ)
The 35-watt light bulb does a work of 46200 joules in 1320 seconds.
Answer:
The required mass is 22.04 g
Explanation:
We know,
Atomic mass of Co= 58g.
Now,
1 mole Co = 58 g
∴ 0.38 mole Co= (58 X 0.38) g
= 22.04 g
So, the required mass is 22.04 g
The first one is color change
Second is the precipitate present
Answer : The molar mass of unknown compound is 152.38 g/mole
Explanation :
Depression in freezing point = ![1.9^oC](https://tex.z-dn.net/?f=1.9%5EoC)
Mass of unknown compound = 16.5 g
Mass of water = 106.0 g
Formula used :
![\Delta T_f=i\times K_f\times m\\\\\Delta T_f=i\times K_f\times\frac{\text{Mass of unknown compound}}{\text{Molar mass of unknown compound}\times \text{Mass of water in Kg}}](https://tex.z-dn.net/?f=%5CDelta%20T_f%3Di%5Ctimes%20K_f%5Ctimes%20m%5C%5C%5C%5C%5CDelta%20T_f%3Di%5Ctimes%20K_f%5Ctimes%5Cfrac%7B%5Ctext%7BMass%20of%20unknown%20compound%7D%7D%7B%5Ctext%7BMolar%20mass%20of%20unknown%20compound%7D%5Ctimes%20%5Ctext%7BMass%20of%20water%20in%20Kg%7D%7D)
where,
= depression in freezing point
i = Van't Hoff factor = 1 (for non-electrolyte)
= freezing point constant for water = ![1.86^oC/m](https://tex.z-dn.net/?f=1.86%5EoC%2Fm)
m = molality
Now put all the given values in this formula, we get
![1.9^oC=1\times (1.86^oC/m)\times \frac{16.5g\times 1000}{\text{Molar mass of unknown compound}\times 106.0g}](https://tex.z-dn.net/?f=1.9%5EoC%3D1%5Ctimes%20%281.86%5EoC%2Fm%29%5Ctimes%20%5Cfrac%7B16.5g%5Ctimes%201000%7D%7B%5Ctext%7BMolar%20mass%20of%20unknown%20compound%7D%5Ctimes%20106.0g%7D)
![\text{Molar mass of unknown compound}=152.38g/mole](https://tex.z-dn.net/?f=%5Ctext%7BMolar%20mass%20of%20unknown%20compound%7D%3D152.38g%2Fmole)
Therefore, the molar mass of unknown compound is 152.38 g/mole