From Q = mcΔΤ, the specific heat capacity, c, of the metal that was cooled is c = Q/mΔT = (-769 J)/(46.4 g)(30.0 °C - 101.0 °C) = 0.233 J/g °C. From the table, it appears that this is the specific heat capacity of silver. So, the metal is most like silver.

Note: The value for Q was written as a negative value in the equation as heat energy was given off by the metal when the metal was cooled (from the metal’s point of view, it’s losing heat energy).

4 0

3 years ago

When scientists looked at the polarity of bands of rock on either side of the mid-ocean ridges, what did they find? A. that ther

alisha [4.7K]

I am pretty sure the answer is D. That the patterns of a polarity matched up on both sides.

3 0

3 years ago

Read 2 more answers

I really need help with this before 5:10

gtnhenbr [62]

CAN YOU HELP ME ANWSER MINE ILL HELP YOU

4 0