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Helga [31]
3 years ago
14

2al(s)+3cl2(g)→2alcl3(s) δh∘ = -1408.4 kj. how much heat (in kilojoules) is released on reaction of 4.70 g of al?

Chemistry
1 answer:
Annette [7]3 years ago
7 0
Answer:
             - 122.58 kJ

Solution:
According to following  equation,

                          <span>2 Al  +  3 Cl</span>₂    <span>→    2 AlCl</span>₃    <span> δH</span>°<span> = -1408.4 kJ
</span>
When,
         54 g (2 mole) Al on reaction releases  =  <span>1408.4 kJ heat
So,
                               4.70 g of Al will release  =  X kJ of Heat

Solving for X,
                      X  =  (4.70 g </span>× 1408.4 kJ) ÷ 54 g

                      X  =  - 122.58 kJ
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