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Helga [31]
4 years ago
14

2al(s)+3cl2(g)→2alcl3(s) δh∘ = -1408.4 kj. how much heat (in kilojoules) is released on reaction of 4.70 g of al?

Chemistry
1 answer:
Annette [7]4 years ago
7 0
Answer:
             - 122.58 kJ

Solution:
According to following  equation,

                          <span>2 Al  +  3 Cl</span>₂    <span>→    2 AlCl</span>₃    <span> δH</span>°<span> = -1408.4 kJ
</span>
When,
         54 g (2 mole) Al on reaction releases  =  <span>1408.4 kJ heat
So,
                               4.70 g of Al will release  =  X kJ of Heat

Solving for X,
                      X  =  (4.70 g </span>× 1408.4 kJ) ÷ 54 g

                      X  =  - 122.58 kJ
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<u><em></em></u>

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Explanation:

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When you work with Temperature in Celsius, and the temperature is placed on the x-axis, the line is shifted to the left  273.15ºC.

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stira [4]

233.1g

Explanation:

Given:

Formula units of FeCl₃ = 8.65 x 10²³ formula units

Unknown:

Mass of the FeCl₃ = ?

Solution:

The formula unit is the same as the amount of subatomic particles in an atom.

  1 mole of a substance = 6.02 x 10²³ formula units

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learn more:

Number of moles brainly.com/question/1841136

#learnwithBrainly

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3 years ago
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