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qaws [65]
1 year ago
6

Find the distance between the points on the graph. Round to one decimal place.

Mathematics
1 answer:
eduard1 year ago
3 0

Answer:

12.0 units

Step-by-step explanation:

The top point is 9 units up and 8 units to the right of the bottom point.

Distance formula: a^2+b^2=c^2

8^2+9^2=c^2

64+81=c

c^2=145

c=12.04 ==> c=12.0 units

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11. The preferred overall competition area in judo, including the mats, is a square with an area of 256 m2.
choli [55]
<span>a) We know that the correct answer will be the square root of 256 since the competition area is a square with an area of 256 meters. And since 10^2 = 100 which is less than 256, the answer has to be greater than 10. And since 20^2 = 400 which is greater than 256, the answer also has to be less than 20. Therefore the answer has to be between 10 and 20. b) The last digit has to be either a 4 or a 6. The units digit is the only digit that will contribute to the units digit of the square. And 0^2 = 0, 1^2 = 1, 2^2 = 4, 3^2 = 9, 4^2 = 16, 5^2 = 25, 6^2 = 36, 7^2 = 49, 8^2 = 64, 9^2 = 81. Of the 10 possible digits, only the values 4 and 6 have a square that has an units digit of 6. c) The square root of 256 based up (a) and (b) above has to be either 14, or 16. So the dimensions are either 14x14 meters or 16x16 meters.</span>
3 0
3 years ago
Help Please!! I am not sure what to do?
Iteru [2.4K]

Answer:

10 < \sqrt{111} < 11

Step-by-step explanation:

The square root of 111 is approximately 10.536.

A number smaller than this is 10.

A number larger than this is 11.

5 0
3 years ago
The line contains the point (-2,-5) and is parallel to 2x-3y = 9.<br> What’s the equation
Karolina [17]

Answer:

y=(2x/3)-(11/3)

Step-by-step explanation:

https://www.emathhelp.net/calculators/algebra-1/parallel-and-perpendicular-line-calculator/

7 0
3 years ago
How 7/3 compares to 2 1/3
alekssr [168]
7/3 written as a mixed fraction is 2 1/3

So 

7/3 = 2 1/3

3 0
3 years ago
The general form of an parabola is 2x2−12x−3y+12=0 .
Murljashka [212]

Answer:

The standard form of the parabola is (x-3)^2=4*\frac{3}{8}(y+2)

Step-by-step explanation:

The standard form of a parabola is

(x-h)^2=4p(y-k).

In order to convert 2x^2-12x-3y+12=0 into the standard form, we first separate the variables:

2x^2-12x+3y+12=0\\\\2x^2-12x+12=3y

we now divided both sides by 2 to remove the coefficient from 2x^2 and get:

x^2-6x+6=\frac{3}{2}y.

We complete the square on the left side by adding 3 to both sides:

x^2-6x+6+3=\frac{3}{2}y+3

x^2-6x+9=\frac{3}{2}y+3

(x-3)^2=\frac{3}{2}y+3

now we bring the right side into the form 4p(y-k) by first multiplying the equation by \frac{2}{3}:

\frac{2}{3} *(x-3)^2=\frac{2}{3} *(\frac{3}{2}y+3)\\\\\frac{2}{3} *(x-3)^2=y+2

and then we multiplying both sides by \frac{3}{2} to get

(x-3)^2=\frac{3}{2} (y+2).

Here we see that

4p=\frac{3}{2}

\therefore p=\frac{3}{8}

Thus, finally we have the equation of the parabola in the standard form:

\boxed{(x-3)^2=4*\frac{3}{8}(y+2)}

5 0
3 years ago
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