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mel-nik [20]
1 year ago
6

A 36-inch string is to be cut so that one piece is 9 inches longer than the other. What is the length of the shorter piece?

Mathematics
1 answer:
Oksanka [162]1 year ago
6 0

Answer:

The shorter piece is 13.5 inches.

Step-by-step explanation:

Let the shorter piece be x inches long. That means the longer piece will be x+9 inches long.

Put the two pieces together and the total is 36 inches:

x + x+9 = 36

Combine like terms.

2x + 9 = 36

Subtract 9 from both sides.

2x = 27

Divide by 2.

x = 13.5

The shorter piece is 13.5 inches. The longer piece is 22.5 inches.

13.5 + 22.5 = 36

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In this case we are given that the vertex is (1,1) so we have:

y=a(x-1)^2+1, and then we are told that there is a point (0,-3) so we can say:

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y=-4(x-1)^2+1

Now you wish to know where the x-intercepts are.  x-intercepts are when the graph touches the x-axis, ie, when y=0 so

0=-4(x-1)^2+1  add 4(x-1)^2 to both sides

4(x-1)^2=1  divide both sides by 4

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x-1=±√(1/4)  which is equal to

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x=1±1/2

So x=0.5 and 1.5, thus the x-intercept points are:

(0.5, 0) and (1.5, 0)  or if you like fractions:

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Then, we can go through the statements.

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Given that,

log_b2 = x\\\\log_b3 = y --------(i)

<em><u>Use the following log rules</u></em>

Rule 1: log_b(ac) = log_ba + log_bc

Rule 2: log_b\frac{a}{c} = log_ba - log_bc

Rule 3: log_ba^c = clog_ba

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Break 162 down to primes:

162 = 2^1 \times 3^4

log_b{162} =log_b 2^1. 3^4\\\\By\ rule\ 1\\\\ log_b{162} = log_b 2^1 +log_b 3^4\\\\By\ rule\ 3\\\\1log_b2 + 4log_b3\\\\1x+4y\\\\x+4y

Thus we get,

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Next

b) log_b 324

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324 = 2^2 \times 3^4

log_b324 = log_b 2^2.3^4\\\\By\ rule\ 1\\\\log_b324 = log_b2^2 + log_b3^4\\\\By\ rule\ 3\\\\log_b324 = 2log_b2 + 4log_b3\\\\From\ (i)\\\\log_b324 = 2x + 4y

Next

c) log_b\frac{8}{9}

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d) \frac{log_b27}{log_b16}

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