Question

Solve the following inequality: 9x+2/3(−7x+6)−1≥2

Answer 1

Answer:

Step-by-step explanation:

3(9x - 14/3x + 4 - 1 ≥ 2)

27x - 14x + 12 - 3 ≥ 6

13x + 9 ≥ 6

13x ≥ -3

x ≥ -3/13

Answer 2

Answer:

x ≥ - $\frac{3}{13}$

Step-by-step explanation:

Given

9x + $\frac{2}{3}$(- 7x + 6) - 1 ≥ 2

Multiply through by 3 to clear the fraction

27x + 2(- 7x + 6) - 3 ≥ 6 ← distribute and simplify left side

27x - 14x + 12 - 3 ≥ 6

13x + 9 ≥ 6 ( subtract 9 from both sides )

13x ≥ - 3 ( divide both sides by 13 )

x ≥ - $\frac{3}{13}$