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NeX [460]
3 years ago
6

Solve the following inequality: 9x+2/3(−7x+6)−1≥2

Mathematics
2 answers:
klasskru [66]3 years ago
5 0

Answer:

Step-by-step explanation:

3(9x - 14/3x + 4 - 1 ≥ 2)

27x - 14x + 12 - 3 ≥ 6

13x + 9 ≥ 6

13x ≥ -3

x ≥ -3/13

dexar [7]3 years ago
5 0

Answer:

x ≥ - \frac{3}{13}

Step-by-step explanation:

Given

9x + \frac{2}{3}(- 7x + 6) - 1 ≥ 2

Multiply through by 3 to clear the fraction

27x + 2(- 7x + 6) - 3 ≥ 6 ← distribute and simplify left side

27x - 14x + 12 - 3 ≥ 6

13x + 9 ≥ 6 ( subtract 9 from both sides )

13x ≥ - 3 ( divide both sides by 13 )

x ≥ - \frac{3}{13}

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What is the solution to this system of equations?
labwork [276]

Answer:

C

Step-by-step explanation:

C. x=7, y=5

4 0
2 years ago
In tests of a computer component, it is found that the mean time between failures is 937 hours. A modification is made which is
VladimirAG [237]

Answer:

Null hypothesis is \mathbf {H_o: \mu > 937}

Alternative hypothesis is \mathbf {H_a: \mu < 937}

Test Statistics z = 2.65

CONCLUSION:

Since test statistics is greater than  critical value; we reject the null hypothesis. Thus, there is sufficient evidence to support the claim that the modified components have a longer mean time between failures.

P- value = 0.004025

Step-by-step explanation:

Given that:

Mean \overline x = 960 hours

Sample size n = 36

Mean population \mu = 937

Standard deviation \sigma = 52

Given that the mean  time between failures is 937 hours. The objective is to determine if the mean time between failures is greater than 937 hours

Null hypothesis is \mathbf {H_o: \mu > 937}

Alternative hypothesis is \mathbf {H_a: \mu < 937}

Degree of freedom = n-1

Degree of freedom = 36-1

Degree of freedom = 35

The level of significance ∝ = 0.01

SInce the degree of freedom is 35 and the level of significance ∝ = 0.01;

from t-table t(0.99,35), the critical value = 2.438

The test statistics is :

Z = \dfrac{\overline x - \mu }{\dfrac{\sigma}{\sqrt{n}}}

Z = \dfrac{960-937 }{\dfrac{52}{\sqrt{36}}}

Z = \dfrac{23}{8.66}

Z = 2.65

The decision rule is to reject null hypothesis   if  test statistics is greater than  critical value.

CONCLUSION:

Since test statistics is greater than  critical value; we reject the null hypothesis. Thus, there is sufficient evidence to support the claim that the modified components have a longer mean time between failures.

The P-value can be calculated as follows:

find P(z < - 2.65) from normal distribution tables

= 1 - P (z ≤ 2.65)

= 1 - 0.995975     (using the Excel Function: =NORMDIST(z))

= 0.004025

6 0
3 years ago
Stacey and Jeremy sent out 380 invitations They have received 127 responses. What does q represent in the equation 380- q = 127
Maslowich
Q represents how many they did NOT recieve

380-127= 253

Now let's check

380-253= 127

CHECK

So q represents 253(the number of invitations they did NOT recieve)


Hope this helps!
7 0
3 years ago
Write an equation of a polynomial with the given characteristics: a quadratic function has x -intercepts of -3 and 1, and a y-in
fredd [130]

Answer:

f(x) = -3(x+3)(x-1)

Step-by-step explanation:

x = -3 & 1; f(x) = 9

f(x) = a(x-r1)(x-r2)

f(0) = a(x-r1)(x-r2) = 9; 9 = a(0-(-3))(0-1)

9 = a(3)(-1); 9 = a(-3)

a = -3

f(x) = -3(x+3)(x-1)

5 0
3 years ago
Read 2 more answers
Which statement is true about the given information ?
solniwko [45]
Yes!! the line AED is cut with a perpendicular line. The rule for perpendicular lines is that the angles made =90.

-This can also be proven by the fact that lines =180, 90+90=180
7 0
3 years ago
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