Which compound is most soluble in water? silver acetate, silver chloride, silver nitrate, silver sulfate?

BRAINLIESTTT ASAP!! PLEASE HELP ME ASAP!

Alexandra [31]

Answer:

Single displacement and reduction

Explanation:

In a single-displacement reaction, one element exchanges partners with another.

$\rm Ca + 2H$_2$O $\longrightarrow$ Ca(OH)$_2$ + H$_2$$

This is a single-displacement reaction, because the element Ca exchanges partners with H.

This is also a reduction/oxidation (redox) reaction, because the optically active of Ca increases from 0 to +2 (oxidation), while the oxidation number of H decreases from +1 to 0 (reduction),

The most common types of reactions are:

Combination
Decomposition
Single displacement
Double displacement
Reduction/oxidation

4 0

2 years ago

Why aren’t subatomic particles, which are smaller than an atom, considered to be the building blocks of matter?

Elena L [17]

Concrete is formed of sand. Is it incorrect to suggest that some houses are built using concrete blocks?

8 0

2 years ago

What is the daughter nucleus (nuclide) produced when 64 Cu Cu64 undergoes beta decay by emitting an electron? Replace each quest

kenny6666 [7]

<u>Answer:</u> The daughter nuclide formed by the beta decay of given isotope is $_{30}^{64}\textrm{Zn}$

<u>Explanation:</u>

Beta decay is defined as the process in which beta particle is emitted. In this process, a neutron gets converted to a proton and an electron.

The released beta particle is also known as electron.

$_Z^A\textrm{X}\rightarrow _{Z+1}^A\textrm{Y}+_{-1}^0\beta$

We are given:

Parent isotope = $_{29}^{64}\textrm{Cu}$

The chemical equation for the beta decay process of $_{29}^{64}\textrm{Cu}$ follows:

$_{29}^{64}\textrm{Cu}\rightarrow _{30}^{64}\textrm{Zn}+_{-1}^0\beta$

Hence, the daughter nuclide formed by the beta decay of given isotope is $_{30}^{64}\textrm{Zn}$

4 0

3 years ago

Consider the reaction of peroxydisulfate ion (S2O2−8) with iodide ion (I−) in aqueous solution: S2O2−8(aq)+3I−(aq)→2SO2−4(aq)+I−

kolbaska11 [484]

Answer:

r = 3.61x $10^{-6}$ M/s

Explanation:

The rate of disappearance (r) is given by the multiplication of the concentrations of the reagents, each one raised of the coefficient of the reaction.

r = k. $[S2O2^{-8} ]^{x} x [I^{-} ]^{y}$

K is the constant of the reaction, and doesn't depends on the concentrations. First, let's find the coefficients x and y. Let's use the first and the second experiments, and lets divide 1º by 2º :

$\frac{r1}{r2} = \frac{0.018^{x} x0.036^{y} }{0.027^xx0.036^y}$

$\frac{2.6x10^{-6}}{3.9x10^{-6}} = (\frac{0.018}{0.027})^xx(\frac{0.036}{0.036})^y$

$0.67 = 0.67^x$

x = 1

Now, to find the coefficient y let's do the same for the experiments 1 and 3:

$\frac{r1}{r3} = \frac{0.018x0.036^y}{0.036x0.054^y}$

$\frac{2.6x10^{-6}}{7.8x10^{-6}} = (\frac{0.018}{0.036})x(\frac{0.036}{0.054})^y$

$0.33 = 0.5x 0.67^y$

$0.67 = 0.67^y$

y = 1

Now, we need to calculate the constant k in whatever experiment. Using the first :

$2.6x10^{-6} = kx0.018x0.036$ $kx6.48x10^{-4} = 2.6x10^{-6}$

k = 4.01x10^{-3} M^{-1}s^{-1}[/tex]

Using the data given,

r = $4.01x10^{-3}x1.8x10^{-2}x5.0x10^{-2}$

r = 3.61x $10^{-6}$ M/s

7 0

2 years ago

Tough and malleable form of iron is

Alenkasestr [34]

The answer to your question is A. Wrought iron because amongst its other properties, wrought iron becomes soft at red heat, and can be easily be forged and forge welded.

4 0

3 years ago

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