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Kipish [7]
2 years ago
11

What is the maximum number of electrons that any 'p' sublevel can hold? 2 electrons 6 electrons 8 electrons 10 electrons

Chemistry
2 answers:
Varvara68 [4.7K]2 years ago
6 0
6 electrons... 's' can hold 2..... 'd' can hold 10 and 'f' can hold 14
BaLLatris [955]2 years ago
3 0

Answer:

6 electrons

Explanation:

With the quantum model of the atom, initiated by Bohr, the orbital (space where is more probably to find the electron) was divided into quantum numbers.

The principal number (n), is the number of the shell, it goes from 1 to 7 and is represented by the letter K, L, M, N, O, P, Q. The maximum number of electrons in the shells are, K = 2, L = 8, M = 18, N = 32, O = 32, P = 18, Q =8.

The secondary number (l) is the subshells, and it goes from 0 to 4 and is represented, in order, for the letter, s, p, d, f. The maximum number of electrons permitted in each subshell is s = 2, p = 6, d = 10, f = 14.

The magnetic number (ml), is represented by orbitals, and it goes from -l to +l, passing by 0. The maximum number of electrons is 2 for each one.

The spin number (ms) refers to the rotation of the electron, and it can be +1/2 or -1/2.

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Two months later 13.8 milligrams of the barium-131 still be radioactive.

<h3>How is the decay rate of a radioactive substance expressed ? </h3>

It is expressed as:

A = A_{0} \times (\frac{1}{2})^{t/T}

where,

A = Amount remaining

A₀ = Initial Amount

t = time

T = Half life

Here

A₀ = 0.50g

t  = 2 months = 60 days

T = 11.6 days  

Now put the values in above expression we get

A = A_{0} \times (\frac{1}{2})^{t/T}

   = 0.50 \times (\frac{1}{2})^{60/11.6}

   = 0.50 \times (\frac{1}{2})^{5.17}

   = 0.50 × 0.0277

   = 0.0138 g

   = 13.8 mg          [1 mg = 1000 g]

Thus from the above conclusion we can say that Two months later 13.8 milligrams of the barium-131 still be radioactive.

Learn more about the Radioactive here: brainly.com/question/2320811

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Disclaimer: The question was given incomplete on the portal. Here is the complete question.

Question: Suppose that 0.50 grams of ban that 0.50 grams of barium-131 are administered orally to a patient. Approximately many milligrams of the barium would still be radioactive two months later? The half-life of barium-131 is 11.6 days.

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A flexible container has 5.00 L of nitrogen gas at 298 K. If the temperature is increased to 333 K, what will be the new volume
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Explanation:

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Calculate the value of 0.1394÷0.004 showing all workings​
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Can car oil degrade carbon fiber?​
KonstantinChe [14]
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A solution of 0.20 M NaOH is used to prepare 0.10 M NaOH. How much of the 0.20 M solution is needed to prepare 455 mL of the dil
maxonik [38]

Taking into account the definition of dilution, 227.5 mL of the 0.20 M solution is needed to prepare 455 mL of the diluted NaOH.

<h3>What is Dilution</h3>

Dilution is the process of reducing the concentration of solute in solution, which is accomplished by simply adding more solvent to the solution at the same amount of solute.

In a dilution the amount of solute does not change, but as more solvent is added, the concentration of the solute decreases, as the volume (and weight) of the solution increases.

A dilution is mathematically expressed as:

Ci×Vi = Cf×Vf

where

  • Ci: initial concentration
  • Vi: initial volume
  • Cf: final concentration
  • Vf: final volume

<h3>Initial volume</h3>

In this case, you know:

  • Ci= 0.20 M
  • Vi= ?
  • Cf= 0.10 M
  • Vf= 455 mL

Replacing in the definition of dilution:

0.20 M× Vi= 0.10 M× 455 mL

Solving:

(0.10 M× 455 mL)÷ 0.20 M= Vi

<u><em>227.5 mL= Vi</em></u>

In summary, 227.5 mL of the 0.20 M solution is needed to prepare 455 mL of the diluted NaOH.

Learn more about dilution:

brainly.com/question/6692004

brainly.com/question/16343005

brainly.com/question/24709069

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