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ICE Princess25 [194]
3 years ago
7

Solve the formula for the indicated variable. k=g-d/c for g

Mathematics
2 answers:
Murrr4er [49]3 years ago
8 0
Just like any other variable, we complete the same process

k = g -  \frac{d}{c}  \\ k  +  \frac{d}{c}  = g \\  \frac{kc + d}{c} = g \\
Now we can test it, let's say k=4, d=6, and c=2, let's find the value of g
4 = g -  \frac{6}{2} \\ 4  +  3 = g \\ 7= g

OR

\frac{kc + d}{c} = g \\   \\  \frac{(4 \times 2) + (6)}{(2)} = g \\  \frac{14}{2}  = g \\ g = 7

mariarad [96]3 years ago
5 0

k=g-d/c for g


Switch sides to get g on left side


G-d/c= k


Add d/c both sides to get g alone


G= d/c+k


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Mashcka [7]

Answer:

6/7

Step-by-step explanation:

because there are 28 properties in all

4 of them are railroads

but we're not looking for the probability of selecting a railroad, which would be 4/28 or 1/7, but for not selecting a railroad

and 24 of them are not railroads

So the probability of not selecting a railroad is 24/28, which simplified/reduced is 6/7

6 0
2 years ago
According to the Square Root property of Equations, the solution set of x2 = 25 is {±5}.
Gala2k [10]
Justify "<span>x2 = 25 is {±5}"

First, please write x^2, not x2.

</span><span>x^2 = 25; solve for x.  Take the sqrt of both sides.  Must write "plus or minus " in front of the sqrt of 25:

x^2 = 25 becomes x = plus or minus 5, so x: {-5, 5}</span>
7 0
3 years ago
Write an equation in slope-intercept form for the line with slope -3/4 and y intercept -3
oksian1 [2.3K]
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y = mx + b

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m is the slope
and b is the y-intercept

the y-intercept is just what y is equal to when x is 0, so right at the middle of the graph.

so just go ahead and if in!

y =  -  \frac{3}{4} x - 3
7 0
3 years ago
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vitfil [10]
Try this option.
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6 0
3 years ago
Which shows the following expression after the negative exponents have been eliminated?
SVETLANKA909090 [29]

Answer:

\frac{a^3b^4}{ab^2} which is the last choice in the question

Step-by-step explanation:

Simplify

\frac{a^3b^{-2}}{ab^{-4}} = \frac{a^3}{a}\frac{b^{-2}}{b^{-4}}

Using the fact that \frac{x^m}{x^n}  =x^{m-n}

We get

\frac{a^3}{a} = a^{3-1} = a^2

\frac{b^{-2}}{b^{-4}} = b^{-2-(-4)} = b^2

So

\frac{a^3b^{-2}}{ab^{-4}} =a^2b^2

Multiplying numerator and denominator by ab^2 gives

a^2b^2 \frac{ab^2}{ab^2}

= \frac{a^3b^4}{ab^2} ANSWER

Hint:

We can eliminate first choice since negative exponents still remain

We can eliminate third choice because the expression has a minus sign which is not possible

That just leaves second and fourth choices to work with

7 0
1 year ago
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