1. <span> Fp = Mg*sin24 = 0.407Mg. </span>
<span>Fn = Mg*Cos24 = 0.914Mg. </span>
<span>Fk = u*0.914Mg. </span>
<span>Fp-Fk = M*a. </span>
<span>0.407Mg-u*0.914Mg = M*a.
</span>Divide by Mg:
<span>0.407-0.914u = a/g = 3.1/-9.81, </span>
<span>0.407-.914u = -0.316, uk = 0.791.
</span>
2. <span> M*g = 1200*9.8 = 11,760 N. = Wt. of car. = Normal force(Fn). </span>
<span>Fp = Mg*sin 0 = 0. </span>
<span>Fk = uk*Fn = 0.1323*11,760 = 1556 N. </span>
<span>Fp-Fk = M*a. </span>
<span>0-1556 = 1200a, a = -1.30 m/s^2. </span>
<span>V^2 = Vo^2 + 2a*d. </span>
<span>0 = (20.1)^2 - 19.6d
</span>
Linear measurements in construction most often expressed using the Common American foot/inch. In some instances metric measurements are used.
Answer:
The frequency of radio waves with a wavelength of 20m is
1.5 e+7 Hertz (Hz) or 15 million Hertz.
This was obtained from the formula speed (c) is equal to the product of frequency (f) and wavelength (λ)
c = fλ
Since we are looking for the frequency, we will divide both sides of the formula above by the lamda symbol for wavelength, which gives us:
f = c / λ
The value of wavelength is already given which is 20 meters. The speed of radio waves is the same with the speed of light when travelling in a vacuum – also with the other electromagnetic waves. Hence the speed (c) is 3 e+8 m/s
f = 3 e+8 m/s / 20m
f = 1.5 e+7 H
Explanation:
this is the correct answer you want.
Complete question is;
A bicycle and a car start their journey at the same time the cyclist reaches it's top speed of 10m/s in 15 s, the car reaches a speed of 15 m/s in 55 s. which has the greater acceleration the car or the bicycle.
Answer:
The bicycle has the greater acceleration.
Explanation:
Cyclist reaches a top speed of 10m/s in 15 s.
Formula for acceleration here is;
a = v/t
a = 10/15
a = 0.67 m/s²
Car reaches a speed of 15 m/s in 55 s.
Thus;
a = 15/55
a = 0.27 m/s²
From the 2 acceleration values gotten, we can say that;
The bicycle has the greater acceleration.