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likoan [24]
3 years ago
12

4. What is the frequency of an electromagnetic wave with a wavelength of 20 m?

Physics
1 answer:
blsea [12.9K]3 years ago
6 0

Answer:

The frequency of radio waves with a wavelength of 20m is

1.5 e+7 Hertz (Hz) or 15 million Hertz.

This was obtained from the formula speed (c) is equal to the product of frequency (f) and wavelength (λ)

c = fλ  

Since we are looking for the frequency, we will divide both sides of the formula above by the lamda symbol for wavelength, which gives us:

f = c / λ

The value of wavelength is already given which is 20 meters. The speed of radio waves is the same with the speed of light when travelling in a vacuum – also with the other electromagnetic waves. Hence the speed (c) is 3 e+8 m/s

f = 3 e+8 m/s   /    20m

f = 1.5 e+7 H

Explanation:

this is the correct answer you want.

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In the form of radioactive decay known as alpha decay, an unstable nucleus emits a helium-atom nucleus, which is called an alpha
trapecia [35]

Answer:

Velocity will be v=4.06\times10^7m/sec

Explanation:

We have given mass of alpha particle m = 4 u =4\times 1.67\times 10^{-27}kg=6.68\times 10^{-27}kg

Charge on alpha particle q=2e=2\times 1.6\times 10^{-19}C=3.2\times 10^{-19}C

Charge on thorium particle =90\times 1.6\times 10^{-19}=144\times 10^{-19}C

Diameter is given as d = 15 fm

So radius r=\frac{d}{2}=\frac{15}{2}=7.5fm=7.5\times 10^{-15}m

Potential energy is given by E=\frac{1}{4\pi \epsilon _0}\frac{q_1q_2}{r}=\frac{Kq_1q_2}{r}=\frac{9\times 10^9\times 144\times 10^{-19}\times 3.2\times 10^{-19}}{7.5\times 10^{-15}}=5.529\times 10^{-12}J

From energy conservation \frac{1}{2}mv^2=5.529\times 10^{-12}

\frac{1}{2}\times 6.68\times 10^{-27}v^2=5.529\times 10^{-12}

v=4.06\times10^7m/sec

6 0
3 years ago
The only force acting on a 2.9 kg canister that is moving in an xy plane has a magnitude of 7.5 N. The canister initially has a
Elodia [21]

Answer:15.66 J

Explanation:

mass of block \left ( m\right )=2.9 kg

Force magnitude=7.5 N

Initial velocity =3.9\hat{i} m/s

Final velocity=5.1 \hat{j} m/s

Initial Kinetic Energy=\frac{1}{2}mv^2

=\frac{1}{2}\times 2.9\times 3.9^2=22.05 J

Final Kinetic Energy=\frac{1}{2}mv^2

=\frac{1}{2}\times 2.9\times 5.1^2=37.714 J

Work Done =Final -Initial Kinetic energy=37.714-22.056=15.66 J

7 0
4 years ago
A 2.3 kg cart is rolling across a frictionless, horizontal track towards a 1.5 kg cart that is initially held at rest. The carts
Inga [223]

Answer:

total momentum = 8.42 kgm/s

velocity of the first cart is 3.660 m/s

Explanation:

Given data

mass m1 = 2.3 kg

mass m2 = 1.5 kg

final velocity V2 = 4.9 m/s

final velocity V3 = - 1.9 m/s

to find out

total momentum  and velocity of the first cart

solution

we know mass and final velocty

and initial velocity of second cart V1 = 0

so now we can calculate total momentum that is m1 v2 + m2 v2

total momentum =  2.3 ×4.9 + 1.5 ×(-1.9)

total momentum = 8.42 kgm/s

and

conservation of momentum  is

m1 V + m2 v1  = m1 v2  + m2 v3

put all value and find V

2.3 V + 1.5 ( 0) = 2.3 ( 4.9 ) + 1.5 ( -1.9)

V = 8.42 / 2.3

V = 3.660 m/s

so velocity of the first cart is 3.660 m/s

8 0
4 years ago
The image above was taken by the spacecraft Messenger as it flew by the planet Mercury. The terrain shown in this image is typic
lorasvet [3.4K]
The answer is

C


Hope this helps
7 0
3 years ago
Right hand rule exercise
saveliy_v [14]

Answer:

A yxiigxih5dd8yixc99uf8g

6 0
3 years ago
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