<h2><u><em>
Firstly we calculate the resistance of the bulb,</em></u></h2><h2><u><em>
</em></u></h2><h2><u><em>
According to Ohm’s Law</em></u></h2><h2><u><em>
</em></u></h2><h2><u><em>
R=V/I Where,R=Resistance , V=Voltage ,I=Current..</em></u></h2><h2><u><em>
</em></u></h2><h2><u><em>
100w at 220v, I=P/V.</em></u></h2><h2><u><em>
</em></u></h2><h2><u><em>
=100/220=0.454Amp.</em></u></h2><h2><u><em>
</em></u></h2><h2><u><em>
R=V/I; 220/0.454=484.56 ohms.</em></u></h2><h2><u><em>
</em></u></h2><h2><u><em>
When it is connected to 240 Volts</em></u></h2><h2><u><em>
</em></u></h2><h2><u><em>
I=V/R; 240/484.56=0.495 ~ 0.50 Amps.</em></u></h2><h2><u><em>
</em></u></h2><h2><u><em>
Power consumed(P)=V×I; 240×0.50=120 W.</em></u></h2><h2><u><em>
</em></u></h2><h2><u><em>
The bulb will consume 120 W at 240 Volts. 20W difference.</em></u></h2><h2><u><em>
</em></u></h2><h2><u><em>
This is not a loss the bulb glows brighter than it used in 220 volts..</em></u></h2>
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